A 2cm diameter cylindrical solenoid of 10 loops and 20cm long

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SUMMARY

The discussion focuses on calculating the electromotive force (EMF), current, magnetic field at the center, and self-inductance of a cylindrical solenoid with a diameter of 2cm, 10 loops, and a length of 20cm, subjected to a changing magnetic field from 0.7 Tesla to 2.7 Tesla over 100ms. The relevant equations include EMF = -dΦ/dt and the magnetic field inside the solenoid given by B = μ₀NI/L. The participants clarify the use of magnetic flux and the importance of the change in magnetic field (ΔB) in their calculations.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the equations for magnetic flux and EMF
  • Knowledge of solenoid characteristics and formulas
  • Basic proficiency in calculus for rate of change calculations
NEXT STEPS
  • Study the derivation and application of Faraday's Law of Induction
  • Learn about the self-inductance formula for solenoids
  • Explore the concept of magnetic flux in varying magnetic fields
  • Investigate the relationship between current, resistance, and EMF in circuits
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone involved in electromagnetic theory and applications, particularly those focusing on solenoids and inductance calculations.

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Homework Statement



A 2cm diameter cylindrical solenoid of 10 loops and 20cm long is in a perpendicular magnetic field of 0.7Tesla directed away from you. The field increases to 2.7Tesla in 100ms. The loop has 8Ω.
What is the EMF?
What is the current?
What is the magnetic field of the center of the current?
What is the self inductance of the solenoid?


Homework Equations



Don't know where to start? Do I use the Bfield that the solenoid is in or the ΔB? When I used B with the eq: I=2radius / μN , I got an extreme current.

The Attempt at a Solution



Am I using the right equations?
eq: B = μNI / 2 radidus

 
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how do you find flux?

well flux is

[itex]\Phi[/itex]=∫B*dA

emf is the time rate of change of the magnetic field

EMF= -[itex]\frac{d\Phi}{dt}[/itex]

which in your case would be -(B2-B1)/t

To find the B field inside a solenoid you are going to need to do an amperian loop

to find i think B=μoNI/L

that should be enough to find what you need
 


Liquidxlax said:
how do you find flux?

well flux is

[itex]\Phi[/itex]=∫B*dA

emf is the time rate of change of the magnetic field

EMF= -[itex]\frac{d\Phi}{dt}[/itex]

which in your case would be -(B2-B1)/t

To find the B field inside a solenoid you are going to need to do an amperian loop

to find i think B=μoNI/L

that should be enough to find what you need

Thank you ... [itex]\Phi[/itex]=∫B*dA... This equation helped a lot.
 

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