A 5cm long, 30g lead bullet strikes a wall at 27°C and melts on the wa

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A 5cm long, 30g lead bullet strikes a wall at 27°C and melts upon impact, prompting questions about its speed, the force exerted on the wall, and the resulting temperature of a 1kg marble wall. The calculated heat energy (Q) is 2.24 Joules, and the force on the wall is determined to be 59.1 x 10^3 Newtons. There is a request for clarification on the calculations for Q, including the specific values used for specific heat capacity, temperature change, and the melting point of lead. The discussion emphasizes the need for accurate calculations to solve for the temperature change of the marble wall. Overall, the thread focuses on the physics principles involved in the scenario presented.
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Homework Statement


A 5cm long, 30g lead bullet strikes a wall at 27°C and melts on the wall without splatter.
How fast was it going?
What is the force on the wall?
If the wall is made of 1kg of marble, what temperature will it reach?



Homework Equations


I don't know how to find the temp of the marble...


The Attempt at a Solution



Q = ΔMcΔT
I found Q=2.24Joules
Force is 59.1 * 10^3 Newtons
 
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Physics8o8 said:

Homework Statement


A 5cm long, 30g lead bullet strikes a wall at 27°C and melts on the wall without splatter.
How fast was it going?
What is the force on the wall?
If the wall is made of 1kg of marble, what temperature will it reach?



Homework Equations


I don't know how to find the temp of the marble...


The Attempt at a Solution



Q = ΔMcΔT
I found Q=2.24Joules
Force is 59.1 * 10^3 Newtons
Welcome to Physics Forums! :smile:

Can you show how you calculated Q and the Force? I get something different for Q.

Your calculation for Q should include the values you used for c, ΔT, and the melting point of lead.
 

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