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A bit of help with KCL and ohms law please

  • #1
i have attached a picture showing the problem;
just wanting to know if my working out and reasoning is correct please.

http://img29.imageshack.us/img29/5412/questionsq.jpg [Broken]

The Attempt at a Solution


i have used KCL to answer (a) and (b) and have answers 0.6 and 1 respectively.

for (c) and (d) i have used the equation v1=r1/(r1+r2)*v
and have answers 1 and 5 repectively.

for (e) i used power equation p=VI where V is 6 and I is 1 and have the answer 6.
thanks in advance for any help i get :)
 
Last edited by a moderator:

Answers and Replies

  • #2
Char. Limit
Gold Member
1,204
14
I see no picture.
 
  • #3
ah sorry, it appears on mine, if not here is the direct link.


http://img29.imageshack.us/img29/5412/questionsq.jpg [Broken]
 
Last edited by a moderator:
  • #4
vk6kro
Science Advisor
4,081
40
The first two look OK.

What is the voltage across a resistor if it is 12 K and it has 0.4 mA flowing in it?
 
  • #5
as in use Ohm's law to find it out?
 
  • #6
vk6kro
Science Advisor
4,081
40
Yes, you can see two resistors that add up to 12 K.

You need the total voltage across them.
 
  • #7
so v1=0.8 and v2 =4.0?
oh and thankyou for your help :), its really appreciated.
 

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