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A bit of help with KCL and ohms law please

  1. Mar 17, 2010 #1
    i have attached a picture showing the problem;
    just wanting to know if my working out and reasoning is correct please.

    http://img29.imageshack.us/img29/5412/questionsq.jpg [Broken]

    3. The attempt at a solution
    i have used KCL to answer (a) and (b) and have answers 0.6 and 1 respectively.

    for (c) and (d) i have used the equation v1=r1/(r1+r2)*v
    and have answers 1 and 5 repectively.

    for (e) i used power equation p=VI where V is 6 and I is 1 and have the answer 6.
    thanks in advance for any help i get :)
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 17, 2010 #2

    Char. Limit

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    Gold Member

    I see no picture.
     
  4. Mar 17, 2010 #3
    ah sorry, it appears on mine, if not here is the direct link.


    http://img29.imageshack.us/img29/5412/questionsq.jpg [Broken]
     
    Last edited by a moderator: May 4, 2017
  5. Mar 18, 2010 #4

    vk6kro

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    Science Advisor

    The first two look OK.

    What is the voltage across a resistor if it is 12 K and it has 0.4 mA flowing in it?
     
  6. Mar 18, 2010 #5
    as in use Ohm's law to find it out?
     
  7. Mar 18, 2010 #6

    vk6kro

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    Yes, you can see two resistors that add up to 12 K.

    You need the total voltage across them.
     
  8. Mar 19, 2010 #7
    so v1=0.8 and v2 =4.0?
    oh and thankyou for your help :), its really appreciated.
     
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