# A body moving in a straight line with constant accelaration

1. Nov 23, 2011

### VICKZZA

1. The problem statement, all variables and given/known data
A body moving in a straight line with constant accelaration takes 3 seconds and 5 seconds to cover two successive distances of 1m.Find the accelaration?

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Nov 23, 2011

### TaxOnFear

Re: accelaration

Constant Acceleration. Hint is in the question.

3. Nov 23, 2011

### VICKZZA

Re: accelaration

i didnt get u

4. Nov 23, 2011

### TaxOnFear

Re: accelaration

Hmm, seems impossible without more information (i.e. initial or final velocity). Did you copy the question down properly?

5. Nov 23, 2011

### VICKZZA

Re: accelaration

question is right

6. Nov 23, 2011

### HallsofIvy

Staff Emeritus
Re: accelaration

It looks straight forward to me. Take the initial speed to be v and acceleration to be a. Take t= 0 at the beginning of the first second in which the object goes 3 feet.

The distance such an object covers is t seconds is $vt+ (1/2)at^2$. In one second, it will have gone distance v+ (1/2)a. In two seconds it will have gone distance 2v+ 2a. What distance did it go the second second? Set those equal to 3 and 5 and you have two equations to solve for v and a.

7. Nov 23, 2011

### TaxOnFear

Re: accelaration

So simple, nice one.