- #1
VICKZZA
- 22
- 0
Homework Statement
A body moving in a straight line with constant accelaration takes 3 seconds and 5 seconds to cover two successive distances of 1m.Find the accelaration?
HallsofIvy said:It looks straight forward to me. Take the initial speed to be v and acceleration to be a. Take t= 0 at the beginning of the first second in which the object goes 3 feet.
The distance such an object covers is t seconds is [itex]vt+ (1/2)at^2[/itex]. In one second, it will have gone distance v+ (1/2)a. In two seconds it will have gone distance 2v+ 2a. What distance did it go the second second? Set those equal to 3 and 5 and you have two equations to solve for v and a.
Constant acceleration is when the velocity of an object changes at a constant rate over a period of time. This means that the object's speed and direction are changing at a steady pace.
Constant acceleration is calculated by dividing the change in velocity by the change in time. The formula for constant acceleration is a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.
Constant acceleration and uniform motion both involve an object moving in a straight line, but the main difference is that in constant acceleration, the object's velocity is changing at a constant rate, while in uniform motion, the object's velocity remains constant.
Air resistance can affect an object's constant acceleration by slowing it down. As an object moves through the air, it experiences a force in the opposite direction of its motion, which can decrease its acceleration. This is why objects in a vacuum, where there is no air resistance, will maintain a constant acceleration.
Some real-life examples of objects moving in a straight line with constant acceleration include a car accelerating from a stop, a roller coaster going down a hill, and a skydiver falling towards the ground. In all of these cases, the object's velocity is changing at a constant rate, resulting in constant acceleration.