phyico
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Ok so i came upon this question and i have no idea what to do!
limit
x->a
x^n-a^n / x - a
the answer is na^n-1
limit
x->a
x^n-a^n / x - a
the answer is na^n-1
The discussion centers on evaluating the limit of the expression (x^n - a^n) / (x - a) as x approaches a. The solution utilizes l'Hôpital's Rule, confirming that the limit equals n * a^(n-1). This method is effective for resolving indeterminate forms in calculus, particularly when direct substitution leads to a 0/0 scenario.
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