- #1
stonecoldgen
- 109
- 0
10. y=sin(lnx) find y'
im not sure how to do this, the previews question was actually with y=ln(sinx), which i know how to do, but not this one.
I know that the derivative of lnx is 1/x and the derivative of sinx=cosx
16.y=10[(x)2-sinx] find y'
PD: that is 10 to the power of (x2-sinx)
i know i should put a ln at both sides of the equation to use logarithmic differentiation, i know the logarithm properties. However, i don't know how should i apply all of that exactly.
EDIT: i also need help finding y' in y=x3-ln(x/e)
Thanks.
im not sure how to do this, the previews question was actually with y=ln(sinx), which i know how to do, but not this one.
I know that the derivative of lnx is 1/x and the derivative of sinx=cosx
16.y=10[(x)2-sinx] find y'
PD: that is 10 to the power of (x2-sinx)
i know i should put a ln at both sides of the equation to use logarithmic differentiation, i know the logarithm properties. However, i don't know how should i apply all of that exactly.
EDIT: i also need help finding y' in y=x3-ln(x/e)
Thanks.