10. y=sin(lnx) find y'(adsbygoogle = window.adsbygoogle || []).push({});

im not sure how to do this, the previews question was actually with y=ln(sinx), which i know how to do, but not this one.

I know that the derivative of lnx is 1/x and the derivative of sinx=cosx

16.y=10[(^{x})^{2}-sinx] find y'

PD: that is 10 to the power of (x^{2}-sinx)

i know i should put a ln at both sides of the equation to use logarithmic differentiation, i know the logarithm properties. However, i don't know how should i apply all of that exactly.

EDIT: i also need help finding y' in y=x^{3}-ln(x/e)

Thanks.

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# Homework Help: A few derivative questions

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