Kaushik said:
Is ##\Delta K.E + \Delta G.P.E + \Delta E.P.E = W_{ncf}## ,where 'ncf' stands for non conservative force?
With minor caveats, it is correct yes. You've split up all the forces acting on an object into three categories.
1. Gravitational force. Associated with a potential named "G.P.E."
2. Other forces that have associated potentials. Associated with an aggregate potential named "E.P.E."
3. Other forces not associated with potentials.
The equation comes, of course, from the work-energy theorem: ##\Delta K.E. = W = \Sigma F\cdot d##
You've simply taken the work from gravity and from all the other conservative forces and moved the associated terms over to the energy side of the equation as potentials. Since the potentials are defined in terms of the work done over a path, this is a perfectly valid thing to do.
Minor caveats:
The gravitational field has to be static. No gravitational slingshots.
If the object upon which work is being done is extended and is either non-rigid or is rotating then we need to compute the work done on the object by considering all external forces as acting on its center of mass. We need to compute the resulting kinetic energy based on total mass and the motion of the center of mass only. (i.e. we need to use center-of-mass work and bulk kinetic energy).