- #1
Feldoh
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I'm just sort of looking for some clarification on some of this...
1) Say we have an ideal emf (battery, I guess...) connected in a circuit to a resistor and nothing else, why is the current the same on either side of the resistor? My textbook doesn't really explain this that well, but I think it's because charge is conserved, and if we pick any two points on the circuit the "flow" of electrons has to be the same for charge to be conserved.
2) So because of this, can we think of resistor as applying a resistance over the entire loop as opposed to one part of it? This seems weird to me because when we draw a circuit diagram representing this situation the resistor is included in only one part of the circuit as opposed over the entire loop, is there a reason for this?
3) Because of this resistors essentially have the effect of decreasing the current at any point in the loop by decreasing the the charge flow over a time interval, correct?
4) When talking about DC circuits we can consider the ideal emf as the work done per charge. When we talk about an emf in terms of work, we're talking about the ability of the emf to (literally?) pump electrons through the actual emf device, correct?
I have a few more questions, but if these are wrong there would be no point in asking them lol, so I'll save the rest for later...
1) Say we have an ideal emf (battery, I guess...) connected in a circuit to a resistor and nothing else, why is the current the same on either side of the resistor? My textbook doesn't really explain this that well, but I think it's because charge is conserved, and if we pick any two points on the circuit the "flow" of electrons has to be the same for charge to be conserved.
2) So because of this, can we think of resistor as applying a resistance over the entire loop as opposed to one part of it? This seems weird to me because when we draw a circuit diagram representing this situation the resistor is included in only one part of the circuit as opposed over the entire loop, is there a reason for this?
3) Because of this resistors essentially have the effect of decreasing the current at any point in the loop by decreasing the the charge flow over a time interval, correct?
4) When talking about DC circuits we can consider the ideal emf as the work done per charge. When we talk about an emf in terms of work, we're talking about the ability of the emf to (literally?) pump electrons through the actual emf device, correct?
I have a few more questions, but if these are wrong there would be no point in asking them lol, so I'll save the rest for later...
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