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amcavoy
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I have a few questions related to statics and rotational dynamics. I have the general idea of what I need to do (at least, I hope I do), but I am having trouble making anything of it. Any input on any of the questions would be greatly appreciated 
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\tau=rF=\left(.05\text{N}\right)\left(.01\text{m}\right)=.0005\,\text{Nm}
...now dividing by the larger radius I can find the contact force, which should be equal to the frictional force in magnitude (is this right?):
\frac{.0005\,\text{Nm}}{.026\,\text{m}}=.019\,\text{N}
Thank you very much for the help.
.The first thing I did was to look at the hanging mass and determine the forces acting on it. I said that the net force is T-1600N=0. Now for the system to remain in equilibrium, I made some assumptions: First, I though of S as a vector. For that vector to remain still, the torque produced by the tension in the direction of the point where the cable is attached to the ground and the torque produced by the tension in the direction of the hanging mass (downwards) must be zero. However, using the first equation I wrote above, I come up with the tension being equal to 1600N. Am I on the right track here?
I know that the answer to part (c) is RIGHT because it is rolling right producing a contact force to the left, thus a frictional force to the right. This is how I attempted to calculate part (a):
\tau=rF=\left(.05\text{N}\right)\left(.01\text{m}\right)=.0005\,\text{Nm}
...now dividing by the larger radius I can find the contact force, which should be equal to the frictional force in magnitude (is this right?):
\frac{.0005\,\text{Nm}}{.026\,\text{m}}=.019\,\text{N}
Thank you very much for the help.
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