Building Gauss Meter with Hall Effect or Mosfets - CoolMagnetMan

  • Thread starter Thread starter prince7
  • Start date Start date
  • Tags Tags
    Gauss
AI Thread Summary
A project is underway to measure magnetic fields, and a gauss meter design using a Hall effect transistor is sought, but the specific transistor is unavailable in Egypt. Alternatives such as using MOSFETs are being considered. An easier method to measure magnetic fields involves using wire, an op-amp, a resistor, a capacitor, and a voltmeter, applicable in a uniform field of sufficient size. This approach leverages Faraday's Law, relating voltage and magnetic flux. The discussion highlights the need for accessible components to achieve accurate magnetic field measurements.
prince7
Messages
2
Reaction score
0
im working in a project requires a measuring of magnetic Fields
all i need right now is a device to build up a gauss meter i have found a one using a hall effect
transistor here in this link http://www.coolmagnetman.com/magmeter.htm
but these hall effect transistor isn't found in Egypt
so anyone can tell me ant other device can be used
like a certin transistor maybe Mosfets
thanks;
 
Physics news on Phys.org
There is an easy way to measure magnetic fields using only wire, an op-amp, a resistor, capacitor, and a voltmeter, if you have a big enough volume of uniform field (about a 5-cm cube). This because Faraday's Law may be written

∫V·dt = -∫B·dA

(So volts times seconds = Teslas times m2)

See my post # 27 in

https://www.physicsforums.com/showthread.php?t=70290&highlight=flip+coil&page=2

Bob S
 
Thread 'Gauss' law seems to imply instantaneous electric field'

Thread 'Gauss' law seems to imply instantaneous electric field'

Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
View full post »

Thread 'Do electron density waves accompany EM waves in coaxial cables?'

Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...
View full post »

Similar threads

Need an electromagnet to play Chess
Replies
37
Views
3K
A Bernoulli, lift and cause & effect
Replies
30
Views
4K
Building a Safe and Efficient Induction Heater Circuit: Tips and Tricks
Replies
7
Views
6K
Build a H-Bridge Circuit: Tips & Info
Replies
10
Views
8K
Engineering Building a peripheral for obtaining data from water
Replies
4
Views
2K
Enlighten me about the differences of IGBT and MOSFET please
Replies
2
Views
2K
Hall Effect sensor to monitor home electrical apparatus
Replies
9
Views
6K
Electric Motorcycle Drive & Hall Effect Sensor Ringing
Replies
1
Views
2K
Hall Effect Lab (Germanium SC) Without Hall Effect Sensor
Replies
1
Views
2K
Non magnetic linear displacement system for moving a Hall Sensor
Replies
11
Views
2K

Hot Threads

Recent Insights

Back
Top