Going through permutations, perhaps it is better to start off with a smaller number to get a feeling of what I'm working with. Let me take number 4. I can form ##4!/(2!2!)## pairs composed of two different numbers from the set ##\{1,2,3,4\}##, right? This is equal to 6. However this is still bigger than the actual number, which I did by hand and is 4, i.e., 4 = 4 = 3 + 1 = 2 + 2 + 2 = 2 + 1 + 1. That must be because in the calculation I did, I included 3 + 3 and 4 + 4. So I would have to figure out a way of removing those combinations that sum up to a number greater than the number I'm considering.
So I'm not sure this method is useful.