A Leak in a Bicycle Tire Problem

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BrainMan
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Homework Statement


Printed textbook problem 71: an inflated bicycle inner tube 2.2 cm in diameter and 200 cm in circumference, a small leak drops gauge pressure from 110 psi to 80 psi at 20°C, asks mass of air lost, assuming pure nitrogen.


Homework Equations


pV = nRT

The Attempt at a Solution



I assumed that volume and temperature would stay constant. I assumed the volume wouldn't change because the volume of the tire doesn't change. This implies that

n1/p1 = n2/p2

n1p2 / p1 = n2

I found n1 by using the ideal gas law

pV/RT = n1 = 0.0592 moles of gas

Then I used the first equation to find n2 = 0.0431 moles.

Subtracting n1 - n2 I found that 0.0161 moles of gas escaped from the tire.

Converting the amount of moles lost to grams I get

0.0161 x 28 g N2/ 1 mol N2 = 0.451 g of N2 gas

The correct answer should be 1.8 g
 
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  • Printed textbook problem 71: An inflated bicycle inner tube is 2.2 cm in diameter and 200 cm in circumference. A small leak causes the gauge pressure to decrease from 110 psi to 80 psi on a day when the temperature is 20°C. What mass of air is lost? Assume the air is pure nitrogen.
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Chestermiller said:
Show us how you got the initial mass of nitrogen.
OK I see. I made an error in calculating the volume of the tire.
 
BrainMan said:
OK I see. I made an error in calculating the volume of the tire.
The ideal gas law uses absolute pressures, not gauge pressures.