A little help with thermo

  • Thread starter neo2478
  • Start date
Can somebody please shed a little light on what this formula represents in the physical world?
And how could I solve it to get [tex]\Delta H[/tex]?

\left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}
humm ..looks like entropia. Or may be i'm completly wrong.
So, you are saying that
\left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \Delta S
Last edited:
no i wrote that, but i'm not saying that :-).
Anyway should be something about Gibbs-Helmholtz equation, but i don't remeber much about it.
So something about chemistry and termodinamics application usually.


\left[\frac{\partial \Delta G}{\partial T}\right]_p = -\Delta S


But wait a reply from someone that know of what is talking about because i'm not sure.
Gibbs Helmholtz
Note d(1/T)/dT is 1/T2. Solve for H. Cancel terms.
So Enthalpy can be obtained from plot of deltaG/T vs 1/T

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