Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A little help with thermo

  1. Apr 9, 2008 #1
    Can somebody please shed a little light on what this formula represents in the physical world?
    And how could I solve it to get [tex]\Delta H[/tex]?

    \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}
  2. jcsd
  3. Apr 9, 2008 #2
    humm ..looks like entropia. Or may be i'm completly wrong.
  4. Apr 9, 2008 #3
    So, you are saying that
    \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \Delta S
    Last edited: Apr 9, 2008
  5. Apr 9, 2008 #4
    no i wrote that, but i'm not saying that :-).
    Anyway should be something about Gibbs-Helmholtz equation, but i don't remeber much about it.
    So something about chemistry and termodinamics application usually.


    \left[\frac{\partial \Delta G}{\partial T}\right]_p = -\Delta S


    But wait a reply from someone that know of what is talking about because i'm not sure.
  6. Apr 9, 2008 #5
    Gibbs Helmholtz
    Note d(1/T)/dT is 1/T2. Solve for H. Cancel terms.
    So Enthalpy can be obtained from plot of deltaG/T vs 1/T
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: A little help with thermo
  1. Thermo Help for exam (Replies: 1)