A little help with thermo

1. Apr 9, 2008

neo2478

Can somebody please shed a little light on what this formula represents in the physical world?
And how could I solve it to get $$\Delta H$$?

$$\left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}$$

2. Apr 9, 2008

PhilippH

humm ..looks like entropia. Or may be i'm completly wrong.

3. Apr 9, 2008

neo2478

So, you are saying that
$$\left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \Delta S$$
?

Last edited: Apr 9, 2008
4. Apr 9, 2008

PhilippH

no i wrote that, but i'm not saying that :-).
Anyway should be something about Gibbs-Helmholtz equation, but i don't remeber much about it.
So something about chemistry and termodinamics application usually.

$$\left[\frac{\partial \Delta G}{\partial T}\right]_p = -\Delta S$$

But wait a reply from someone that know of what is talking about because i'm not sure.

5. Apr 9, 2008

hslilly

Gibbs Helmholtz
Note d(1/T)/dT is 1/T2. Solve for H. Cancel terms.
So Enthalpy can be obtained from plot of deltaG/T vs 1/T

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