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A little help with thermo

  1. Apr 9, 2008 #1
    Can somebody please shed a little light on what this formula represents in the physical world?
    And how could I solve it to get [tex]\Delta H[/tex]?

    [tex]
    \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}
    [/tex]
     
  2. jcsd
  3. Apr 9, 2008 #2
    humm ..looks like entropia. Or may be i'm completly wrong.
     
  4. Apr 9, 2008 #3
    So, you are saying that
    [tex]
    \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \Delta S
    [/tex]
    ?
     
    Last edited: Apr 9, 2008
  5. Apr 9, 2008 #4
    no i wrote that, but i'm not saying that :-).
    Anyway should be something about Gibbs-Helmholtz equation, but i don't remeber much about it.
    So something about chemistry and termodinamics application usually.

    [tex]

    \left[\frac{\partial \Delta G}{\partial T}\right]_p = -\Delta S

    [/tex]

    But wait a reply from someone that know of what is talking about because i'm not sure.
     
  6. Apr 9, 2008 #5
    Gibbs Helmholtz
    Note d(1/T)/dT is 1/T2. Solve for H. Cancel terms.
    So Enthalpy can be obtained from plot of deltaG/T vs 1/T
     
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