A particle P is projected from a point O with velocity

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A particle P is projected from point O with a velocity of 12i + 16j, and after two seconds, another particle Q is projected from the same point, colliding with P one second later. The collision occurs three seconds after P's projection, allowing for the calculation of P's position at that time. The key to solving the problem lies in determining the horizontal and vertical distances traveled by both particles to find the initial velocity of Q. The discussion emphasizes the importance of accurately interpreting the timing of the projections and the collision. Understanding these time intervals is crucial for solving the problem effectively.
VICKZZA
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Homework Statement


A particle P is projected from a point O with velocity 12i +16j .two seconds later,another particle Q is projected from O and collides with P after another second.Find the initial velocity of Q.


Homework Equations



x=(vcosθ)(t)
y=vtsinθ-1/2gt^2

The Attempt at a Solution

i think that Q will approach P when ts vertical and horizontal distance become equal with P.but i can't handle the time change or its accurates valuess...pleasezz help me out.....
 
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How many seconds does the first particle spend in flight before the collision? What is the x,y location of the collision?
 


its not given in the question
 


VICKZZA said:
its not given in the question

Sure it is. Reread the question statement carefully.
 


its not there
 


VICKZZA said:
its not there

Yes, it is.


P is projected. 2 seconds later, Q is projected. Another second later, they collide.


Collision happens, 2 + 1 = 3 seconds after P is projected. From there, you should be able to easily work out the location of collision (where is P 3 seconds after projection?).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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