A particle P is projected from a point O with velocity

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Homework Help Overview

The problem involves two particles, P and Q, with P being projected from a point O with a given velocity. The scenario describes the timing of their projections and the conditions for their collision.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the timing of the projections and the conditions for collision, questioning how to handle the time differences and the corresponding positions of the particles.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the timing of the projections and the necessary calculations for the collision. Some guidance has been provided regarding the timing of the collision and the need to determine the location of particle P at that time.

Contextual Notes

There is a lack of explicit information regarding the flight duration of particle P before the collision, which has led to some confusion among participants. The problem requires careful consideration of the timing and positions of both particles.

VICKZZA
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Homework Statement


A particle P is projected from a point O with velocity 12i +16j .two seconds later,another particle Q is projected from O and collides with P after another second.Find the initial velocity of Q.


Homework Equations



x=(vcosθ)(t)
y=vtsinθ-1/2gt^2

The Attempt at a Solution

i think that Q will approach P when ts vertical and horizontal distance become equal with P.but i can't handle the time change or its accurates valuess...pleasezz help me out.....
 
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How many seconds does the first particle spend in flight before the collision? What is the x,y location of the collision?
 


its not given in the question
 


VICKZZA said:
its not given in the question

Sure it is. Reread the question statement carefully.
 


its not there
 


VICKZZA said:
its not there

Yes, it is.


P is projected. 2 seconds later, Q is projected. Another second later, they collide.


Collision happens, 2 + 1 = 3 seconds after P is projected. From there, you should be able to easily work out the location of collision (where is P 3 seconds after projection?).
 

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