A problem about spherical pendulum that filled with water

AI Thread Summary
The discussion revolves around a hollow spherical pendulum filled with water and how its oscillation period changes as the water empties through a hole. Key factors include the changing mass and inertia of the sphere, which complicate the calculations. The center of mass shifts as the water level decreases, affecting the effective length of the pendulum. Initially, the oscillation period increases as the sphere empties, but it eventually returns to its original value. The problem highlights the complexities of analyzing dynamic systems with changing mass distribution.
amirghaderi
Messages
21
Reaction score
0
We have a hollow spherical pendulum that is filled with water. The sphere has a hole under it. If it starts to oscillate and at the beginning it was full of water, how it’s period would be by passing time and empting sphere?
 
Physics news on Phys.org
amirghaderi said:
We have a hollow spherical pendulum that is filled with water. The sphere has a hole under it. If it starts to oscillate and at the beginning it was full of water, how it’s period would be by passing time and empting sphere?
Welcome to PF amirghaderi,

Well I suppose the first question to ask yourself is that what property changes as the water empties from the sphere?
 
the mass and the inertia of the sphere changes
 
amirghaderi said:
the mass and the inertia of the sphere changes
Indeed it does. However, the problem is greatly simplified because usually a spherical pendulum is seen as a generalisation of a simple pendulum in three-space, which means that we can ignore the moment of inertia of the sphere and just consider the pendulum as a point mass suspended by a massless string.

EDIT: So, now you need to decide how the position of the centre of mass of the sphere varies with time.
 
Last edited:
We only need to find the effective "l" for the pendulum which is the distance of the centre of mass from the point of attaching of the string.
 
Hence... the problem. This sounds like some sort of twisted related rates problem. From the sort of question you posted, I imagine you know how to calculate your moments of inertia (and maybe are familiar with the tensor forms even)... sounds like you just need to express the rate of change of mass for the volume of water within the sphere. Neglecting the mass of the sphere itself, as Hottenanny already mentioned.
 
i am graduated student in physics and i knonw how to calculate its moments of inertia but and how to simply ignore it as a point mass but i can't reach its answer that is first its period becomes large and then becomes smaler and without ignoreing the inertial momentom of the sphere solving becomes very complicated and did not look a meaning ful answer
 
amirghaderi said:
i am graduated student in physics and i knonw how to calculate its moments of inertia but and how to simply ignore it as a point mass but i can't reach its answer that is first its period becomes large and then becomes smaler and without ignoreing the inertial momentom of the sphere solving becomes very complicated and did not look a meaning ful answer
Consider where the centre of mass of the hollow sphere is located at the following points:

(a) When it is full of water
(b) When it is half full of water
(c) When it is empty
 
Last edited:
thanx mr Hootenanny for your hint .
i solve it .
the period first increses and then retern to the orginal value
 
  • #10
amirghaderi said:
thanx mr Hootenanny for your hint .
i solve it .
the period first increses and then retern to the orginal value
It's a pleasure :smile:
 
Back
Top