A question of Einstein field equation

chinared
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I got some trouble from this question:
For a given metric: ds2 =t-2(dx2-dt2), derive the energy-momentum tensor which satisfies the Einstein equation: Rαβ- 1/2Rgαβ=8\piGTαβ.

I got the Ricci scalar R=2, but Tαβ=0 for all α,β. Does this means a curved spacetime without any source(energy-momentum tensor)? Is this possible? Or this result implies that I have made some mistakes in my calculation?

Thanks for answering this question!
 
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A schwarzschild black hole is a curved spacetime with no stress-energy tensor, so yes.
 
A correction to the EFE as you've written them

Rαβ- (R/2)gαβ=8πGTαβ.

I hope it is a typo. (added later ) I see you fixed it after I posted.

Your result is possible as Nabeshin has said.

[edit]
I did the calculation and your results are correct.
 
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I've got a question about this problem. I'm not completely new to GR, but I'm new to actual calculations because I've focused mostly on concepts and I haven't taken a GR class.

How can one find the value of the Ricci Scalar from a given metric? And what about the Stress Energy tensor?
 
From the Christoffel symbols,
<br /> {\Gamma ^{m}}_{ab}=\frac{1}{2}g^{mk}(g_{ak,b}+g_{bk,a}-g_{ab,k})<br />
the Riemann tensor follows,
<br /> {R^{r}}_{mqs} = \Gamma ^{r}_{mq,s}-\Gamma ^{r}_{ms,q}+\Gamma ^{r}_{ns}\Gamma ^{n}_{mq}-\Gamma ^{r}_{nq}\Gamma ^{n}_{ms}<br />
from which
<br /> R_{ms}={R^{r}}_{mrs}<br />
and so
<br /> R=g^{ms}R_{ms}<br />

Use Maxima or some other CAS to calculate this stuff - it takes days by hand.
 
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