A question on alternating current

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Kudo Shinichi
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Homework Statement


The peak value of an alternating current in a 1500W device is 5.4A. What is the rms voltage (root-mean-square voltage)across it?

The Attempt at a Solution


Peak current=sqrt(2)*Irms
5.4A=sqrt(2)*Irms
Irms=3.82A
Irms=P/Vrms
3.82=1500/Vrms
Vrms=392.84V

I am not sure whether this is the correct way to do the question or not, because it seems to simple...Any comment/help would be great. Thank you very much.
 
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This is, in fact, the correct way to do it, easy though it may seem.
 
jdougherty said:
This is, in fact, the correct way to do it, easy though it may seem.

thank you very much^^