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A question on alternating current

  1. Mar 16, 2009 #1
    1. The problem statement, all variables and given/known data
    The peak value of an alternating current in a 1500W device is 5.4A. What is the rms voltage (root-mean-square voltage)across it?

    3. The attempt at a solution
    Peak current=sqrt(2)*Irms
    5.4A=sqrt(2)*Irms
    Irms=3.82A
    Irms=P/Vrms
    3.82=1500/Vrms
    Vrms=392.84V

    I am not sure whether this is the correct way to do the question or not, because it seems to simple...Any comment/help would be great. Thank you very much.
     
  2. jcsd
  3. Mar 16, 2009 #2
    This is, in fact, the correct way to do it, easy though it may seem.
     
  4. Mar 16, 2009 #3
    thank you very much^^
     
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