A quick question about friction and applied force

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If the friction force exceeds the applied force, the object remains stationary, resulting in zero acceleration. According to Newton's First Law, when acceleration is zero, the applied force equals the friction force, indicating balanced forces. If the applied force is less than the static friction, the object does not move, maintaining a state of rest. Once an object is in motion, if the applied force equals the friction force, it can achieve constant velocity without acceleration. Overall, understanding the relationship between applied force and friction is crucial for predicting an object's motion.
pyroknife
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if the friction force is larger than the applied force. the object wouldn't move and the acceleration would be 0 right?
 
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If the friction force is larger than the applied force, The net force would move with the force of friction. in essence the Force of friction would become the applied force, the applied force would slow it down (apply friction)

Newtons First Law: if a = 0; F_{applied} = F_{friction} meaning any time acceleration is zero, the forces are balenced and equal each other, if Ff is greater than Fp, e.g. Ff = 60 N, Fp = 50 N

Fnet would be -10N as Fnet = Fp - FF

Fnet = 50N - 60N
Fnet = -10N so it would move and accelerate backwards.
 
Senjai said:
If the friction force is larger than the applied force, The net force would move with the force of friction. in essence the Force of friction would become the applied force, the applied force would slow it down (apply friction)

Newtons First Law: if a = 0; F_{applied} = F_{friction} meaning any time acceleration is zero, the forces are balenced and equal each other, if Ff is greater than Fp, e.g. Ff = 60 N, Fp = 50 N

Fnet would be -10N as Fnet = Fp - FF

Fnet = 50N - 60N
Fnet = -10N so it would move and accelerate backwards.
No. If the applied force to an object is less than the static friction, the object does not move. The applied force will be balanced by an equal and opposite static force.
 
so that means acceleration=0 and not a negative number right?
 
pyroknife said:
so that means acceleration=0 and not a negative number right?
The force is static, hence no motion (i.e. no change in velocity), hence no acceleration.

This assumes an object at rest.


If one can get an object moving, and then the applied force equals the friction force, one can have a constant velocity, but no acceleration.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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