A rational function which I forget how to integrate

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Homework Help Overview

The original poster seeks assistance with integrating a rational function, specifically \(\int \frac{x}{x^{4}-1} dx\), and expresses uncertainty about the integration method when the denominator cannot be factored.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Some participants suggest the use of Partial Fraction Decomposition, noting the need to rewrite the function in terms of simpler fractions. Others question the original poster's assertion about the irreducibility of the denominator and discuss the requirements for the degrees of the numerator and denominator in this context.

Discussion Status

The discussion is active, with participants providing insights into the method of Partial Fraction Decomposition and clarifying the conditions for the degrees of polynomials involved. There is an ongoing exploration of the reasoning behind the setup of the decomposition.

Contextual Notes

Participants note that the original poster's example may not be the best choice, as the denominator can indeed be factored. There is also mention of the general rule regarding the degrees of the numerator and denominator in partial fraction decomposition.

Damascus Road
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Hey all!

It's been a while since I've done this, how do you integrate a rational function, where the denominator cannot be factored, again?

For example, [tex]\int \frac{x}{x^{4}-1} dx[/tex]


Thanks, in advance!
 
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The denominator can be factored, though. The method you're probably thinking of is called Partial Fraction Decomposition.

You want to rewrite x/(x^4 - 1) as A/(x - 1) + B/(x + 1) + (Cx + D)/(x^2 + 1).
Solve for A, B, C, and D.
 
That's not a very good example:smile:...the denominator can be factored.

edit Mark beat me to it :cry:
 
I should've seen that... my bad. However,
can you explain why you placed Cx + D above the irreducible part, instead of just "C"?

Thanks!
 
Damascus Road said:
I should've seen that... my bad. However,
can you explain why you placed Cx + D above the irreducible part, instead of just "C"?

Thanks!

For the method of partial fraction decomposition, in general, the numerator of each term must be of degree one less than the degree of the corresponding denominator. The last term has a 2nd degree polynomial for the denominator, so you ,in general, require a first degree polynomial for the numerator.

P.S. the reason I wrote "in general" in the above statement, is that sometimes you will find C=0.
 

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