A runner weighs 687 N and 71% of this weight is water. (a) H

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A runner weighing 687 N has 71% of their weight as water, leading to a calculation of approximately 49.77 g of water in their body. The initial conversion from weight to mass was incorrectly calculated as 70.1 g instead of 70.1 kg, which significantly affects the results. The correct number of moles of water is approximately 2.765, calculated using the molar mass of water. This leads to an estimate of about 1.665 x 10^23 water molecules in the runner's body. The discussion highlights the importance of unit conversion in physics problems.
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Homework Statement


A runner weighs 687 N and 71% of this weight is water. (a) How many moles of water are in the runner's body? (b) How many water molecules (H2O) are there?

Homework Equations


n = N/NA
n= m/mass per mole
NA = 6.022E23
F=ma
H: 2*1
O: 16

The Attempt at a Solution


a)
687/9.8=70.1 g
70.1 * .71 = 49.77 g of h20
49.77/18 u = 2.765

b) 6.022E23 * 2.765 = 1.665
 
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Alice7979 said:
70.1 g
His mass is only 70.1 grams?! Check your units.
Alice7979 said:
6.022E23 * 2.765 = 1.665
What happened to the E23?
 
Alice7979 said:

The Attempt at a Solution


a)
687/9.8=70.1 g
70.1 * .71 = 49.77 g of h20
49.77/18 u = 2.765
Is this reasonable? A man who weighs 70.1 grams? Must be a world record...

(Posted at the same time as haruspex, oops)
 
Last edited:
I forgot the formula was in kg
 
Alice7979 said:
I forgot the formula was in kg
So does that change your answer?
 
haruspex said:
So does that change your answer?
Yes it did, thanks
 
Nathanael said:
(Posted at the same time as haruspex, oops)
Always happy to have corroboration.
 

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