- #1
Bill Foster
- 338
- 0
I was wonder if anybody might know how to solve this (this is not a homework problem, btw).
The Lorentz Force is given by:
[tex]\vec{F}=q(\vec{E}+\vec{v}\times\vec{B})[/tex]
Now afer working that out, I get three differential equations:
[tex]\frac{dv_x}{dt}=\frac{q}{m}(E_x+v_yB_z-v_zB_y)[/tex]
[tex]\frac{dv_y}{dt}=\frac{q}{m}(E_y+v_zB_x-v_xB_z)[/tex]
[tex]\frac{dv_z}{dt}=\frac{q}{m}(E_z+v_xB_y-v_yB_x)[/tex]
So far so good. But I can't solve these differential equations because we have [tex]\frac{dv_x}{dt}[/tex] as a function of [tex]v_y[/tex] and [tex]v_z[/tex]
I would be thankful if anyone would show me how to solve such a system of differential equations.
The Lorentz Force is given by:
[tex]\vec{F}=q(\vec{E}+\vec{v}\times\vec{B})[/tex]
Now afer working that out, I get three differential equations:
[tex]\frac{dv_x}{dt}=\frac{q}{m}(E_x+v_yB_z-v_zB_y)[/tex]
[tex]\frac{dv_y}{dt}=\frac{q}{m}(E_y+v_zB_x-v_xB_z)[/tex]
[tex]\frac{dv_z}{dt}=\frac{q}{m}(E_z+v_xB_y-v_yB_x)[/tex]
So far so good. But I can't solve these differential equations because we have [tex]\frac{dv_x}{dt}[/tex] as a function of [tex]v_y[/tex] and [tex]v_z[/tex]
I would be thankful if anyone would show me how to solve such a system of differential equations.