The Explosion of a Vessel and Velocity of its Pieces

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Homework Help Overview

The discussion revolves around a physics problem involving the explosion of a vessel into three pieces, focusing on the conservation of momentum and kinetic energy. The scenario describes two pieces of equal mass moving perpendicularly with a specified speed, while the third piece has a greater mass, prompting questions about its velocity after the explosion.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the conservation of momentum and kinetic energy, questioning the relevance of potential energy in the context of the explosion. There are discussions about the initial conditions, particularly the initial kinetic energy and momentum being zero, and how that affects the calculations for the third piece's velocity.

Discussion Status

Participants are actively engaging with the problem, with some clarifying misconceptions about initial kinetic energy and momentum. There is an acknowledgment of the conservation laws that need to be applied, and one participant has indicated progress in solving for the velocity of the third piece.

Contextual Notes

There is confusion regarding the initial kinetic energy being zero and the implications of that on the conservation laws. The problem setup involves specific mass relationships and directions of motion that are critical to the discussion.

Rave Grrl
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I need some help on how to solve this question, I don't really know how to do this at all.

A vessel at rest explodes, breaking into three pieces. Two pieces having equal mass, fly off perpendicular to one another with the same speed of 30 m/s. The third piece has three times the mass of each other piece. What are the magnitude and direction of it's velocity immediately after the explosion?

I was told that the sum of the potential energy has to equal the final kinetic energy, but isn't there no potential energy at the beginning? :confused:
 
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You don't need to know anything about the potential energy. Whatever chemical potential energy there was has been expended (the problem states immediately after the explosion) so all you have to concern yourself with is the initial kinetic energy and momentum of the fragments and, of course, both of those quantities will be conserved.
 
So the sum of the energy and momentum has to equal zero? Since the initial kinetic energy was zero?
 
Rave Grrl said:
So the sum of the energy and momentum has to equal zero? Since the initial kinetic energy was zero?

In the initial situation,the KE of the body was zero.The momentum of the body was zero.

Hopefully u can project the momentum conservation law on the 2/3 axes of coordinates and with use of the KE conservation law,u can find your answers.

Daniel.

EDIT:OOOOOOOOOOOOOOOOOPSSSSSSSSSSSS!The KE cannot be zero in the initial case,since it would be zero at the end,too,therefore it would be no moving around...
I'm an idiot!
 
Last edited:
The initial kinetic energy is NOT zero! However, the momentum vector is.
 
The Kinetic Energy will increase as you can see... the initial energy is 0. It probably has chemical potential energy but that's not relevant. MOMENTUM IS CONSERVED. Which means that:

<br /> m_1v_1&#039; + m_2v_2&#039; + m_3v_3&#039; = 0<br />
 
When I try to solve for V3 in that equation I keep getting the square root of a negative number...
 
nevermind I figured it out
 

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