A very simple question about antimatter and E=mcc

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Annihilating equal amounts of matter and antimatter results in the conversion of both masses into energy, following the equation E=mc². For instance, 1 kg of matter and 1 kg of antimatter would yield a total energy output of 2Xc², effectively producing 2Xc² joules. The example of a positron and an electron, each with a mass of 511 keV, illustrates this principle, resulting in two 511 keV photons upon annihilation. Therefore, both matter and antimatter contribute to the total energy produced. This confirms that antimatter does indeed 'count' in energy calculations.
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My question is simple: suppose that I have X kg of matter and an equal amount of antimatter, would *both* produce Xc^2 amount of energy upon annihilation, resulting in a total of E=2Xc^2? In other words, would the antimatter 'count'? (So if I take 1 kg of matter and 1 kg of antimatter, I would get 2c^2 J of energy?)It seems obvious to me, but I don't want to make a simple mistake - not yet knowing all the details about antimatter and stuff - and screw up my calculations.
 
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All the mass (matter plus antimatter) gets converted to energy. Simplest example: positron + electron. Each have mass of 511 kev. Output is 2 511 kev photons.
 
mathman said:
All the mass (matter plus antimatter) gets converted to energy. Simplest example: positron + electron. Each have mass of 511 kev. Output is 2 511 kev photons.

Thank you. That answered my question. :smile:
 
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