About 2 vehicles going down hill

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Discussion Overview

The discussion revolves around the dynamics of two identical vehicles descending a hill, one carrying a heavier load than the other. Participants explore the effects of mass on acceleration and the conditions under which the vehicles would reach the bottom of the hill, considering factors like air resistance, friction, and rolling motion.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions which vehicle will reach the bottom first, suggesting that the answer depends on various assumptions.
  • Another participant argues that, under typical conditions, the heavier vehicle will reach the bottom first, but acknowledges that in the absence of air resistance and friction, both would arrive simultaneously.
  • A participant seeks clarification on why the heavier vehicle would reach first, specifically questioning the equivalence of inertial mass between the two vehicles.
  • Discussion includes the concept of "rolling mass" and how it affects acceleration, with one participant explaining that the heavier vehicle accelerates slightly more due to the effective mass being less than proportional to the actual mass.
  • Another participant notes that in a perfect scenario with zero friction, the vehicles would slide rather than roll.
  • The conversation shifts to a related topic about flywheels in race cars, discussing how moment of inertia affects performance and acceleration, which some participants find relevant to the initial discussion.
  • Clarifications are sought regarding the relationship between effective mass and moment of inertia, with participants providing mathematical relationships to explain their reasoning.

Areas of Agreement / Disagreement

Participants express differing views on the effects of mass and rolling motion on the acceleration of the vehicles. While some agree on the theoretical aspects of acceleration, others raise questions about the assumptions and conditions affecting the outcomes, indicating that the discussion remains unresolved.

Contextual Notes

Participants acknowledge the importance of assumptions such as the absence of air resistance and friction, as well as the implications of rolling versus sliding motion. The discussion also touches on the complexities introduced by moment of inertia in real-world applications, such as racing.

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Hi everyone, I have a simple question. 2 identical vehicles(tyres, shape, design) are set free from rest, going downhill. One vehicle is carrying a large weighted object while the other one is not.Hence, one vehicle has a larger mass than the other.

Which vehicle will reach downhill first? or they reach at the same time? in condition both start at the same place and same time in the first place.
 
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Pagedown said:
Hi everyone, I have a simple question. 2 identical vehicles(tyres, shape, design) are set free from rest, going downhill. One vehicle is carrying a large weighted object while the other one is not.Hence, one vehicle has a larger mass than the other.

Which vehicle will reach downhill first? or they reach at the same time? in condition both start at the same place and same time in the first place.

It really depends on a number of assumptions that could be made. However, practially speaking, and considering typical conditions, the heavier object will reach the bottom first.

Note that, in the absense of air resistance and friction and other non-ideal behavior, they would arrive at the same time, since gravitational mass and inertial mass are the same.
 
Why the heavier reaches first then?

Yes, i did mean in the absense of air resistance and friction and other non-ideal behavior.
Is the inertial mass really is the same, considering the larger mass on the other?
 
Hi Pagedown! :smile:

In the absence of air resistance etc, the heavier vehicle will accelerate slightly more, because of the "rolling mass" of the wheels (which you say are the same on each vehicle).

The force on each car is proportional to the mass, but to find the acceleration we divide by the "effective mass", which is the actual mass plus I/r2 (I is the moment of inertia ) for each wheel (you can check this using conservation of energy and the "rolling constraint" v = ωr) …

for the heavier car, this is slightly less than proportional to mass. :wink:

(If the cars were sliding instead of rolling the accelerations would be the same,)
 
Note that if you consider perfect ideal case with zero friction, the wheels will not even spin. They will just slide.
 
T- Tim..excellent summary...makes perfect sense on a lot of things..this year we are switching flywheels in the race car..rules dictate that the flywheel can only weigh minimum of 10 pounds..but..for the big dollars there is a legal flywheel that has the ten pound mass concentrated in a 4 inch diameter as opposed to the standard 10 inch diameter...rumor has it this combination really has a quick ramp up to hi RPM..but the driver will stall the car off the grid until he gets used to the low torque during launch and has to spin up the revs until he drops the clutch when starting out...
 
Hi Ranger Mike! :smile:

I'm confused … what is the flywheel attached to? :confused:

(and did you really mean minimum?)
 
Sorry T-tim i should have been more specific
I took the moment of inertia discussion into the realm of rotating weight of components in a race car. The flywheel is the traditional design connecting the crankshaft to the manual transmission. Sanctioning rules limit the weight of rotating and reciprocating components of the race car and there is a minimum weight limit of the flywheel. Lighter weight flywheels launch quicker than heavier flywheels..but heavier flywheel will carry a low horsepower , light weight car deeper into the turn than the light flywheel and this combination will " carry the car thru the turn" faster than the light weigh combo.
The moment of inertia topics is a very good subject for my particular application..thank you
 
tiny-tim said:
Hi Pagedown! :smile:

In the absence of air resistance etc, the heavier vehicle will accelerate slightly more, because of the "rolling mass" of the wheels (which you say are the same on each vehicle).

The force on each car is proportional to the mass, but to find the acceleration we divide by the "effective mass", which is the actual mass plus I/r2 (I is the moment of inertia ) for each wheel (you can check this using conservation of energy and the "rolling constraint" v = ωr) …

for the heavier car, this is slightly less than proportional to mass. :wink:

(If the cars were sliding instead of rolling the accelerations would be the same,)

Why the effective mass is the actual mass+I/r^2 and why it's slightly less than proportional to mass?
 
  • #10
Hi GT1! :smile:

Because mgsinθ - friction = ma,

and friction times r = Iα = Ia/r,

so mgsinθ - Ia/r2 = ma,

ie mgsinθ = (m + I/r2)a …

that bracket is therefore the effective mass. :wink:

(and if you increase m but not I, then the bracket doesn't go up proportionally as much as m)
 

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