- #1

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what does this equal because i'm confused when it has the square root sign on it all and it's absolute value

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- Thread starter afcwestwarrior
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- #1

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what does this equal because i'm confused when it has the square root sign on it all and it's absolute value

- #2

cristo

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- #3

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yup that's what i mean

- #4

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so when i a take the absolute value of it, it looks the same or the square root is gone

- #5

cristo

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Your expression above can be written [itex]+\sqrt{4x+1}[/itex].

- #6

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what happens after i take the absolut value of square root sign4x+1

- #7

- 457

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so that's what it'll look like

- #8

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Your expression above can be written [itex]+\sqrt{4x+1}[/itex].

Actually, his expression can be written [itex]\sqrt{4x+1}[/itex]. Square roots are defined to be a FUNCTION, which means they CAN'T give you more than one result for any number in their domain (i.e. we can't have [itex]\sqrt{4}=\pm 2[/itex]). By convention, [itex]\sqrt{x} \ge 0[/itex] for all [itex]x \in [0,\infty)[/itex].

- #9

cristo

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Actually, his expression can be written [itex]\sqrt{4x+1}[/itex]. Square roots are defined to be a FUNCTION, which means they CAN'T give you more than one result for any number in their domain (i.e. we can't have [itex]\sqrt{4}=\pm 2[/itex]). By convention, [itex]\sqrt{x} \ge 0[/itex] for all [itex]x \in [0,\infty)[/itex].

Good point; thanks for spotting that, Moo!

- #10

HallsofIvy

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