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Absolute Value in a double integral

  1. Dec 3, 2007 #1
    [SOLVED] Absolute Value in a double integral

    1. The problem statement, all variables and given/known data

    If [tex]\Omega[/tex] = [-1,1] x [0,2], evaluate the double integral [tex]\int\int_{\Omega} \sqrt{|y-x^{2}|} dA[/tex] given that it exists.

    2. Relevant equations

    None

    3. The attempt at a solution

    I know that in order to integrate with the absolute value I have to split the integral into two parts: When [tex]x^{2} > y ---> \sqrt{x^{2}-y} [/tex] and [tex]y > x^{2} ---> \sqrt{y-x^{2}} [/tex]

    I just can't get of the limits of the integral. Anyone have any advice on where to start or how to look at it to discover the limits? TIA
     
  2. jcsd
  3. Dec 3, 2007 #2
    n/m, found them out.
     
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