Absorption of energy from a photon?

AI Thread Summary
A photon with energy greater than the excitation energy of an atom can still be absorbed, but the probability decreases as the energy difference increases. If a photon of 3.3 eV strikes an atom requiring 3.2 eV to excite an electron, it may not be absorbed due to this energy difference. However, if the energy exceeds the ionization threshold, the photon will be absorbed, and the excess energy will convert to kinetic energy. The uncertainty principle allows for some flexibility in energy absorption, meaning exact matches are not necessary. Ultimately, the absorption depends on the relationship between photon energy and the atom's energy levels.
sanado
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Hey guys, am studying light and matter at the moment.

Was just wondering:

1. Assuming an atom requires 3.2 eV to transfer an electron to an excited state, if a photon of 3.3eV struck the atom, would it still be absorbed. If so, what happens to the remaining energy
 
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Interesting question... I was pondering about it myself some time ago. One thing is that the energy of the excited state isn't exact, but it has a certain spread due to the Heisenberg uncertainty, so the photon energy doesn't need to be exactly the same as that of the excited level. I guess that the greater the difference between photon energy and excited level, the less probability that the photon will be absorbed. Thus, all energy will be absorbed, if it's absorbed at all.
 
From what I learnt, it won't get absorbed.
Unless 3.2eV's the energy required for ionisation... Then if the photon has energy greater than this ionisation energy, it will get absorbed and the remaining energy will be transferred to kinetic energy.
 
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