AC generator calculation question

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To calculate the emf induced in a coil with dimensions 0.4m by 0.3m, 50 turns, and a flux density of 96.8 mT, the relevant equation is EMF = v l B N sinθ. The velocity v is calculated as 47.13 m/s, leading to an emf of 45.62 V when substituting into the equation. The calculation assumes the coil is rotated 30 degrees from the vertical, with the long sides facing the magnets. The method appears correct based on the provided parameters. The final emf value is confirmed unless there is an error in the initial setup.
Th3_PhYsIcS
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1. Calculate the emf induced in ONE side of a coil of length 0.4m and width 0.3m, when there are 50 turns in the coil and the flux density is 96.8 mT, and the coil is rotated 30 degrees from the vertical. Frequency is 50 Hz and the long sides are the ones facing the magnets.
 
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Relevant equations? Your attempt? Please follow the template.
 
2. Relevant equation(s): EMF = v l B N sinθ

3. My attempt: v = 2 ∏ (0.3/2) * 50 = 47.13 ms-1 ∴ emf = 47.13(0.4)(96.8 * 10^-3)(50)(sin30) = 45.62 V
 
is ^ my method correct. Sorry i am new to these forums
 
Can't find anything wrong, so unless the picture we have of the situation is wrong, that's the emf !
 

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