AC generators and Transformers

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Discussion Overview

The discussion revolves around the behavior of an AC generator when connected to a transformer and the effects of varying load resistance on the system's performance. Participants explore concepts related to power generation, load resistance, energy conservation, and the operational dynamics of generators under different loading conditions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose that connecting a generator to a transformer requires a specific resistance in the secondary coil circuit to match power usage.
  • Others argue that if the resistance is higher, the amperage and power decrease, allowing the generator to operate more easily.
  • Conversely, if the resistance is lower, the load may demand more power than the generator can provide, potentially leading to failure, which may manifest as a shutdown or a reduction in voltage.
  • One participant suggests that energy conservation must be considered, questioning where energy goes when resistance is high.
  • Another participant explains that in a steady state, the power generated must equal the power consumed, and any imbalance will result in changes to the generator's speed or torque.
  • There is a discussion about the role of mechanical torque and how it affects the generator's performance under varying load conditions.

Areas of Agreement / Disagreement

Participants generally agree on the relationship between load resistance and generator performance, but multiple competing views remain regarding the implications of high and low resistance on energy conservation and system behavior. The discussion remains unresolved on some aspects, particularly concerning the specifics of energy flow and conservation in different scenarios.

Contextual Notes

Participants mention the importance of equations governing electrical power and torque, but there are unresolved assumptions regarding the specifics of generator failure modes and the exact nature of energy conservation in the system.

Who May Find This Useful

This discussion may be useful for individuals interested in electrical engineering, power generation systems, and the operational principles of AC generators and transformers.

Biker
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So Assume that I have an AC generator and I am giving it enough power to keep spinning with the same rate. So I have limited power usage. The generator creates maximum voltage V and because power is limited that leaves me with only 1 specific current. Now if I connect this generator to a transformer. The voltage on the secondary coil will be Vs and it depends on the ratio between the number of turns Which means there is only 1 specific resistance should be placed in the secondary coil circuit to satisfy the power usage. What if I place a different resistance? What will happen to this system?
 
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Biker said:
What if I place a different resistance? What will happen to this system?
If the resistance is higher, the amperage and power are lower and the generator just has an easier time.

If the resistance is lower, the load demands more power than the generator can provide and it fails. The exact mode of failure depends on the specifics of the generator and its prime mover, but it may shut down or it may just slow down and lower the voltage until the power drops back into its range.
 
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russ_watters said:
If the resistance is higher, the amperage and power are lower and the generator just has an easier time.

If the resistance is lower, the load demands more power than the generator can provide and it fails. The exact mode of failure depends on the specifics of the generator and its prime mover, but it may shut down or it may just slow down and lower the voltage until the power drops back into its range.
About high resistance, What about energy conservation? where does the energy go?

The low resistance part, I think in the case of giving it the same power it will probably just fail because it won't be able to slow down if I am giving it energy. Which means a bit of fire I guess.
 
Biker said:
So Assume that I have an AC generator and I am giving it enough power to keep spinning with the same rate. So I have limited power usage. The generator creates maximum voltage V and because power is limited that leaves me with only 1 specific current. Now if I connect this generator to a transformer. The voltage on the secondary coil will be Vs and it depends on the ratio between the number of turns Which means there is only 1 specific resistance should be placed in the secondary coil circuit to satisfy the power usage. What if I place a different resistance? What will happen to this system?
The generator will speed up or slow down depending on whether it is underloaded or overloaded.

Let's assume the system without the transformer as the transformer only transfers the power. It won't make any difference.

The input to the generator is mechanical torque. Say your input mechanical torque is 10Nm and your generator is running at N rpm and it generates a voltage of 100V with a load resistance of 100 ohm. Now, the current is 1A and electrical power is 100V*1A=100W. Now, if you added one more 100 ohm resistance in parallel with the load, the equivalent load resistance is 50 ohm, meaning the load is doubled. If your mechanical input torque is constant at 10Nm, the generator will slow down and voltage developed by the generator will drop to 50V. Note that the load current will still be 1A. So the power supplied by the generator will drop to 50W.
 
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cnh1995 said:
The generator will speed up or slow down depending on whether it is underloaded or overloaded.

Let's assume the system without the transformer as the transformer only transfers the power. It won't make any difference.

The input to the generator is mechanical torque. Say your input mechanical torque is 10Nm and your generator is running at N rpm and it generates a voltage of 100V with a load resistance of 100 ohm. Now, the current is 1A and electrical power is 100V*1A=100W. Now, if you added one more 100 ohm resistance in parallel with the load, the equivalent load resistance is 50 ohm, meaning the load is doubled. If your mechanical input torque is constant at 10Nm, the generator will slow down and voltage developed by the generator will drop to 50V. Note that the load current will still be 1A. So the power supplied by the generator will drop to 50W.
So basically, If the load doesn't consume all of the energy supplied, the energy will speed up the generator. If it takes more than it should,then it will take energy more than supplied from the generator which means it will slow down until it reaches equilibrium again.

Really nice.
 
Biker said:
So basically, If the load doesn't consume all of the energy supplied, the energy will speed up the generator. If it takes more than it should,then it will take energy more than supplied from the generator which means it will slow down until it reaches equilibrium again.

Really nice.
Yes. In steady state, power generated= power consumed (+losses). Generators speed up or slow down as per the loading. Power plants have automatic systems which regulate the speeds of their generators by adjusting the mechanical torque.
 
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Biker said:
About high resistance, What about energy conservation? where does the energy go?
Energy is conserved. Check the equations; higher resistance = lower power and low resistance = higher power.
V=IR and P=VI so if "R" goes down, "I" goes up and "P" goes up.
The low resistance part, I think in the case of giving it the same power it will probably just fail because it won't be able to slow down if I am giving it energy. Which means a bit of fire I guess.
If you are giving the generator the same input rotational power and trying to hold the rpm constant, it will have to slow down because there won't be enough torque to keep it spinning at the same rate. Again: check your equations: P= tw [torque times angular speed]

The input and output power must match in a steady-state situation. If they don't, *something* will change to make them become equal. Like an angular acceleration (deceleration).
 
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Biker said:
So basically, If the load doesn't consume all of the energy supplied, the energy will speed up the generator. If it takes more than it should,then it will take energy more than supplied from the generator which means it will slow down until it reaches equilibrium again.
Right: unless there is a controller that can regulate the rotational power (actually just torque, at constant RPM) provided by the prime mover.
 
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