Accelerating car and the person driving it

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    Accelerating Car
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When a car accelerates, the top part of the body appears to move backward due to the inertia of the upper body, which is not immediately accelerated by the car's motion. From an inertial frame, the lower body moves forward with the car, while the upper body lags due to a delay in the net force acting on it. This phenomenon can be visualized by considering the perspective of both an outside observer and the driver inside the car. The discussion also extends to a pendulum in an accelerating train, where both inertial and non-inertial frames perceive the pendulum's angle differently due to the effects of acceleration. Overall, the conversation emphasizes the importance of frame of reference in understanding motion and acceleration.
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Hi

Can anybody explain why the top part of the body goes back when the car accelerates? Can you please explain in terms of Newton's laws.
 
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The top part of the body does not go back: the bottom part goes forward [faster] because it is attached to an accelerating car.
 
Last edited:
vijay_singh said:
Hi

Can anybody explain why the top part of the body goes back when the car accelerates? Can you please explain in terms of Newton's laws.

Just to add a bit to Russ's (correct) answer.
Imagine watching the process from the ground outside the car (an inertial frame) in slow motion. You would see the car start to accelerate and move forwards. The bottom half of the body would do likewise, accelerated by forces from the car seat, which is (obviously) attached to the car. But there is a time-delay until a net force starts to act on the top half of the body (which we can think of as loosely coupled to the bottom half) and so it cannot immediately join in with the forward motion. From the ground it therefore stays still, but form the point of view of the driver (a non-inertial frame) it moves backwards.
 
tonyh said:
Just to add a bit to Russ's (correct) answer.
Imagine watching the process from the ground outside the car (an inertial frame) in slow motion. You would see the car start to accelerate and move forwards. The bottom half of the body would do likewise, accelerated by forces from the car seat, which is (obviously) attached to the car. But there is a time-delay until a net force starts to act on the top half of the body (which we can think of as loosely coupled to the bottom half) and so it cannot immediately join in with the forward motion. From the ground it therefore stays still, but form the point of view of the driver (a non-inertial frame) it moves backwards.

Thanks for detailing it, infact this is exactly the way I wanted to understand. I keep feeling that I have started understanding about motion in accelerated frames, but I come across a scenario which I am not able to explain with the way I understand the laws.

Coming back to your explanation and particularly last sentence. Are you sure that viewed from ground (inertial frame) the head stays still but from non-inertial frame it moves backward?
 
vijay_singh said:
Coming back to your explanation and particularly last sentence. Are you sure that viewed from ground (inertial frame) the head stays still but from non-inertial frame it moves backward?
That is my understanding. Perhaps one of the mentors could comment?
 
vijay_singh said:
Thanks for detailing it, infact this is exactly the way I wanted to understand. I keep feeling that I have started understanding about motion in accelerated frames, but I come across a scenario which I am not able to explain with the way I understand the laws.

Coming back to your explanation and particularly last sentence. Are you sure that viewed from ground (inertial frame) the head stays still but from non-inertial frame it moves backward?

Imagine from the car's frame of reference: The driver is sitting normally, and then throws his head backwards to the seat.

From an inertial frame, the head wouldn't quite be still, as it's attached to the car through the body, but it would move much less than the accelerating car.
 
Thanks guys, i understood it now.

How would we explain following in similar way:

A accelerating train with a pendulum attached to its ceiling. Do we see the same angle it makes from non-inertial frame (train) and inertial frame (ground) and why?
 
vijay_singh said:
A accelerating train with a pendulum attached to its ceiling. Do we see the same angle it makes from non-inertial frame (train) and inertial frame (ground) and why?
The angle will appear the same regardless of the frame of observation (ignoring near light speed affects).
 
vijay_singh said:
A accelerating train with a pendulum attached to it's ceiling. Do we see the same angle it makes from non-inertial frame (train) and inertial frame (ground) and why?

Because from the point of view of the outside, the train+attachment point is accelerating, but the pendulum is still, but from the train's point of view, the train+attachment point is still, but the pendulum is accelerating. However, both will agree that the acceleration is the same, but with opposite signs. (so the train is moving forward for outside perspective, but the pendulum is accelerating backwards for the train perspective.)

grettz...
 
  • #10
Jeff Reid said:
The angle will appear the same regardless of the frame of observation (ignoring near light speed affects).

i think the acceleration will affect the way the pendulum swings. so i don't see how the angle remains unaffected. i m pretty bad at math, so can't work it out. but it doesn't seem right when i think about it.
 
  • #11
jablonsky27 said:
i think the acceleration will affect the way the pendulum swings. so i don't see how the angle remains unaffected. i m pretty bad at math, so can't work it out. but it doesn't seem right when i think about it.

He didn't said the angle will remain unaffected due to acceleration, he said regardless the frame of observation. Different frames will see different accelerations,yes, because the train frame is a non-inertial frame, so it will have fiction forces on it force diagram. However, that fiction force is in magnitude equal to the force observed by a outside frame acting on the train.

Take some time to think about this, imagine and draw 2 force diagrams, one in the train, other outside, and verify for yourself. Don't forget whoever, that the train is non-inertia framel!? dv/dt≠0

(of course, like Jeff Reid right said, this is true assuming v<<c, not considering speed light effects)

grettz
 
  • #12
yeah, my mistake. should have read jeff_reid's post more carefully.
 
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