Acceleration and Tension in Multiple Pulleys

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SUMMARY

The discussion focuses on the dynamics of a system involving two blocks, m1 and m2, connected by massless and frictionless pulleys. The key equations derived include the tension in the rope, T = m1a, and the acceleration of the blocks, a = m2g/(2m1 + m2). Participants debated the assumption of equal acceleration for both masses and explored the implications of the fixed length of the rope on their movements. The conclusion emphasizes the need to analyze the relationship between the movements of m1 and m2 to accurately determine their accelerations.

PREREQUISITES
  • Understanding of Newton's Second Law (Sum(F) = ma)
  • Basic principles of pulley systems
  • Knowledge of kinematics and acceleration
  • Familiarity with tension in ropes and forces in equilibrium
NEXT STEPS
  • Explore the concept of tension in multi-pulley systems
  • Learn about the effects of friction in pulley dynamics
  • Investigate the relationship between acceleration and displacement in connected masses
  • Study advanced problems involving non-constant forces in pulley systems
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Physics students, educators, and anyone interested in mechanics, particularly those studying dynamics and pulley systems.

Lanox
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Homework Statement


Block "m1" sits on a horizontal frictionless surface. Block "m2" is hanging below the pulleys as shown. All of the pulleys are massless and frictionless. Given [m1, m2]. Determine:

a. The tension in each rope.
b. The acceleration of each block.

assignment 5, prob 7.png

Homework Equations


Sum(F) = ma

The Attempt at a Solution


block m1:
F = m1a
Tension = m1a

block m2:
m2g - T - T = m2a
m2g - 2T = m2a
2T = m2g - m2a

*insert tension found through working block m1

2(m1a) = m2g - m2a
2m1a + m2a = m2g
a(2m1 + m2) = m2g
a = m2g/(2m1 + m2)

a. T = m1a
b. Acceleration = m2g/(2m1 + m2)

I've been been looking around the internet and asking my peers about this problem and we all seem to have varying answers. Could someone verify as to whether or not I'm doing this properly?

Thanks
 
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You have assumed both masses have the same acceleration. Do they?
 
Orodruin said:
You have assumed both masses have the same acceleration. Do they?

Hm, might it be that block m1 has a greater acceleration due to the rope pulling directly on it? If so how would the acceleration differ?
 
Lanox said:
Hm, might it be that block m1 has a greater acceleration due to the rope pulling directly on it? If so how would the acceleration differ?
If mass 1 moves 1 cm, how far does mass 2 move? Hint: The rope is likely assumed to have a fixed length.
 
Orodruin said:
If mass 1 moves 1 cm, how far does mass 2 move? Hint: The rope is likely assumed to have a fixed length.
I believe that mass 2 would also move one centimeter, or would the existence of the rope connected to the hook create a different outcome?
 
I suggest you write the length of the rope as a function of the positions of the masses.
 
Lanox said:
I believe that mass 2 would also move one centimeter, or would the existence of the rope connected to the hook create a different outcome?

I recommend a pulley. Connect one to a string and use it to lift something. If you don't have a pulley make one out of a key ring. Just loop the string (or a shoe lace) through the ring and use it to lift the keys, just as you would to lift m2.
 
Supposing mass m2 moves down by 1 cm. How much longer became both vertical pieces of the rope?
The length of the whole rope is constant. How much shorter becomes the horizontal piece?
 

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