Acceleration of a mass down a decline (tricky)

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Homework Help Overview

The problem involves a mass moving up an inclined plane and the calculation of the tension required to reverse its direction within a specified time frame. The incline is set at a 30-degree angle, with a coefficient of kinetic friction provided, and the mass is given as 100 kg. Participants are exploring the dynamics of forces acting on the mass, including gravitational components and friction.

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  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the mass, including gravitational force components and friction. There is an exploration of the equations of motion, particularly focusing on the acceleration needed to reverse the mass's direction. Some participants question the initial assumptions about acceleration and the interpretation of the problem statement.

Discussion Status

There is an ongoing dialogue regarding the correct interpretation of acceleration and the forces involved. Some participants have provided calculations and equations, while others seek clarification on the logic behind these equations. Multiple interpretations of the problem are being explored, particularly concerning the required retardation and the role of tension in the system.

Contextual Notes

Participants are working under the constraints of the problem's parameters, including the specified time for reversal and the physical properties of the incline and mass. There is a noted confusion regarding the acceleration values and their implications for the forces at play.

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The plane is inclined at a 30 degree angle. The coefficient of kinetic friction between the mass and the plane is 0.1. The mass is 100kg. If the mass is moving up the inclined plane at a velocity of 2m/s, what tension should be applied to the rope in order to make the mass reverse directions in exactly 1 sec?



mgsin(theta)
mgcos(theta)
Fk = coefficient x mgcos(theta)
V = Vi + at




V = Vi + at a = 4m/s^2
Equation I used to solve:
ma = mgsin(theta) - T - Fk(theta)


My answer was 187N, actual answer is 387N. No idea how I can manipulate the equation to get 200N more.
 
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can you provide a diagram to make it clear?
 
supratim1 said:
can you provide a diagram to make it clear?

ramp.jpg


Found this on google. The diagram in the book is identical, just ignore the hanging mass. I need to find the tension in the rope.
 
First, to make it reverse direction, required retardation, along the inclined plane is 2
0.1 mg cos30 +mg sin30 - T = 2m

Seems the key here is "make the mass reverse directions" , it just means "make the mass to have 0 velocity in 1 sec" but not "make the mass to have -2 in 1 sec"
 
I believe your acceleration is wrong. It should be 2 m/s2 and in the direction opposite it initial velocity. The velocity has to go from 2 m/s to 0 m/sin a time of 1 s.
 
lswtech said:
First, to make it reverse direction, required retardation, along the inclined plane is 2
0.1 mg cos30 +mg sin30 - T = 2m

Seems the key here is "make the mass reverse directions" , it just means "make the mass to have 0 velocity in 1 sec" but not "make the mass to have -2 in 1 sec"

what is 2m?

edit:
I got the 387N by using your equation, but changed the positions of T and 2m. Can you explain the logic behind your equation. I sort of get it, but I need some clarification.

I understand the force of friction and the downward force of the mass are added because they act in the same direction. And T is in the opposite direction, but how do you explain the 2m?
 
Last edited:
The question stated " make the mass reverse directions in exactly 1 sec" and I thought the retardation should be 2ms^-2 but not 4.

and the 2m means m*a and putting a = 2

Since the direction of retardation is pointing towards the ground, and the Net force in this direction is Friction + Weight component - Tension and the Net acceleration is 2
 
lswtech said:
The question stated " make the mass reverse directions in exactly 1 sec" and I thought the retardation should be 2ms^-2 but not 4.

and the 2m means m*a and putting a = 2

Since the direction of retardation is pointing towards the ground, and the Net force in this direction is Friction + Weight component - Tension and the Net acceleration is 2

So is the acceleration (ma) in the same direction of the Tension?
 
No. Reverse

(Weight pulls down the block and it is the origin of the acceleration downward)
 

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