Acceleration of a Particle in an Elliptical Path

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SUMMARY

The discussion focuses on determining the acceleration of a particle moving in an elliptical path defined by polar coordinates. The relevant equations include R = ab/(b^2+(a^2-b^2)cos(theta)^2)^0.5 and theta(dot) = k/R^2. The participant is advised to use differentiation and the chain rule to find the acceleration, confirming that assuming a constant z-coordinate is appropriate for horizontal motion. The conversation emphasizes the importance of correctly applying cylindrical coordinates to solve the problem.

PREREQUISITES
  • Understanding of polar coordinates and their applications in physics
  • Familiarity with cylindrical coordinates and their equations
  • Knowledge of differentiation and the chain rule in calculus
  • Basic principles of motion in a horizontal plane
NEXT STEPS
  • Study the application of differentiation in polar coordinates
  • Learn about the chain rule in calculus and its practical applications
  • Explore the concepts of acceleration in cylindrical coordinates
  • Investigate the dynamics of elliptical motion in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking for examples of applying calculus to physical problems.

LisaSpace
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Homework Statement


Path of a particle attached to the end of a flexible bar is essentially an ellispe in the horizontal plane.

Determine the acceleration of the particle in an arbitrary position.

Homework Equations



The polar coordinates are:

R = ab/(b^2+(a^2-b^2)cos(theta)^2)^.5

theta(dot) = k/R^2

The Attempt at a Solution



I attempted to solve using the equation for acceleration in cylindrical coordinates, I'd write it out, but I'm not familiar with the code for math symbols.

I assumed z to be constant since motion was in a horizontal plane.

Is this the correct way to go about solving it? If it is then I'll will go and see where I messed up.

Thanks
 
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LisaSpace said:

Homework Statement


Path of a particle attached to the end of a flexible bar is essentially an ellispe in the horizontal plane.

Determine the acceleration of the particle in an arbitrary position.

Homework Equations



The polar coordinates are:

R = ab/(b^2+(a^2-b^2)cos(theta)^2)^.5

theta(dot) = k/R^2

The Attempt at a Solution



I attempted to solve using the equation for acceleration in cylindrical coordinates, I'd write it out, but I'm not familiar with the code for math symbols.

I assumed z to be constant since motion was in a horizontal plane.

Is this the correct way to go about solving it? If it is then I'll will go and see where I messed up.

Thanks

If you know the particle position, then you should be able to get the acceleration through differentiation and the chain rule. So yes, carry on and show us where you think you are messing up. You can use the buttons labeled X2 and X2 for super and sub scripts. There are also various symbols for copy and paste in my signature.
 

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