Acceleration of gravity at pendulum

In summary, the problem involves a 2.00m long pendulum making 84.5 complete oscillations in 4.00 minutes. The goal is to find the acceleration of gravity at that spot. Using the formula T=2(3.14)SQRT(l/g), the attempt at a solution involves solving for g by substituting the given values. However, a mistake is made with the value of T, which should be 4/84.5 minutes per oscillation, or 2.84 seconds per oscillation. Solving for g gives a value of 4.9298 m/s, which could be correct but further clarification is needed.
  • #1
Aamun
10
0

Homework Statement


A pendulum which is 2.00m long makes 84.5 complete oscillations in 4.00 min. What is the acceleration of gravity at that spot? Show all work and formulas.


Homework Equations



T=2(3.14) SQRT(l/g)

The Attempt at a Solution



L= g*(T/2pi)^2
2.00=g*(4.00/6.28)^2
g=4.9298 m/s

-----
I'm not sure if I'm missing a step, or if this is correct.. which is where I run into the problem. I'm also not sure of where the Oscillations would fit in.
 
Physics news on Phys.org
  • #2
T is the number of seconds per oscillation. You can figure this out with the data given.
 
  • #3
So it would be 4/84.5= 0.047 minutes per oscillation = 2.84 oscillations per second?
 
Last edited:
  • #4
2.84 seconds per oscillation, yes.
 
  • #5
If you're trying to find g, wouldn't it be easier to solve the equation for g immediately? But that's not the main problem. The 4 mins is not T, it is the time it takes for 84.5 oscillations, not 1.

EDIT: lol sorry too late :D
 
  • #6
Ok, I got it, thanks a bunch! =)
 

1. What is the definition of acceleration of gravity at a pendulum?

The acceleration of gravity at a pendulum is the rate at which the pendulum's velocity changes due to the force of gravity pulling it towards the center of the Earth. It is typically denoted as "g" and has a constant value of 9.8 m/s² on Earth.

2. How is the acceleration of gravity at a pendulum calculated?

The acceleration of gravity at a pendulum can be calculated using the formula g = 4π²l/T², where l is the length of the pendulum and T is the period of oscillation. This formula is derived from the equation for the force of gravity, F = mg, where m is the mass of the pendulum and g is the gravitational acceleration.

3. Does the acceleration of gravity at a pendulum vary at different points on Earth?

Yes, the acceleration of gravity at a pendulum can vary slightly at different points on Earth due to variations in the Earth's mass distribution. However, these differences are very small and can be considered negligible for most practical purposes.

4. How does the length of a pendulum affect its acceleration of gravity?

The length of a pendulum has a direct effect on its acceleration of gravity. As the length of the pendulum increases, the acceleration of gravity decreases and the period of oscillation increases. This is because a longer pendulum has a larger arc to travel in the same amount of time, resulting in a slower velocity and a lower acceleration of gravity.

5. Can the acceleration of gravity at a pendulum be affected by other factors besides length and mass?

Yes, the acceleration of gravity at a pendulum can also be affected by air resistance and friction. Air resistance can slow down the pendulum's motion, resulting in a lower acceleration of gravity. Friction can also have a similar effect, as it can absorb some of the energy of the pendulum's motion.

Similar threads

  • Introductory Physics Homework Help
Replies
20
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
477
  • Introductory Physics Homework Help
Replies
9
Views
690
  • Introductory Physics Homework Help
Replies
26
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
3K
  • Introductory Physics Homework Help
Replies
5
Views
917
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
16
Views
1K
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
2K
Back
Top