Acceleration of gravity at pendulum

AI Thread Summary
To calculate the acceleration of gravity using a pendulum, the formula T = 2π√(l/g) is applied, where T is the period of oscillation. The pendulum length is 2.00 m, and it completes 84.5 oscillations in 4.00 minutes, leading to a period of approximately 0.047 minutes per oscillation. The correct approach involves converting the total time for oscillations into seconds and then calculating the period. After rearranging the formula to solve for g, the calculated value of acceleration due to gravity is approximately 4.93 m/s². The discussion highlights the importance of correctly interpreting the total time for multiple oscillations versus a single period.
Aamun
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Homework Statement


A pendulum which is 2.00m long makes 84.5 complete oscillations in 4.00 min. What is the acceleration of gravity at that spot? Show all work and formulas.


Homework Equations



T=2(3.14) SQRT(l/g)

The Attempt at a Solution



L= g*(T/2pi)^2
2.00=g*(4.00/6.28)^2
g=4.9298 m/s

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I'm not sure if I'm missing a step, or if this is correct.. which is where I run into the problem. I'm also not sure of where the Oscillations would fit in.
 
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T is the number of seconds per oscillation. You can figure this out with the data given.
 
So it would be 4/84.5= 0.047 minutes per oscillation = 2.84 oscillations per second?
 
Last edited:
2.84 seconds per oscillation, yes.
 
If you're trying to find g, wouldn't it be easier to solve the equation for g immediately? But that's not the main problem. The 4 mins is not T, it is the time it takes for 84.5 oscillations, not 1.

EDIT: lol sorry too late :D
 
Ok, I got it, thanks a bunch! =)
 

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