In QM, something very similar to F=ma is true for expectation values.
Observables like F and a don't have sharp values in QM but obey a probability distribution like the famous bell-shaped Gaussian distribution. For a Gaussian distribution, the expectation value is the peak of the curve and it tells you what you should expect if you measure the observable many times and calculate the mean value. Another important parameter of the distribution is the width of the curve at a certain height (often at half the height of the peak). This is a measure for how you should expect the individual measurement outcomes to spread, i.e. how far they will be from the mean value.
Now in QM, F=ma is a law which is valid for the expectation values of F and a. In general, the formalism of QM doesn't tell you what happens in an individual run of an experiment but only what happens "on average". Only if the spread of the probability distribution was zero, it would be meaningful to talk about what happens in a single run of the experiment (because it would be equal to what happens on average).
In classical mechanics, there's no lower bound to the spread, so it can be zero in principle and F=ma can be viewed as an exact law which tells you what "really goes on" during a single run of the experiment. (However note that this is idealized and that F and a can't be known exactly because of the limited resolution of your experimental apparatus.)
In QM, there's a fundamental lower bound to the spread which is given by Heisenberg's uncertainty principle (HUP). But this bound involves Planck's constant, which is incredibly small compared to everyday scales. So although the spread cannot be zero, it can be very small compared to the expectation value. And if it is smaller than the resolution of your measurement apparatus, the predictions of QM and classical mechanics are exactly the same.
(There are a few technical inaccuracies in what I wrote above but I think they are justified in order to make the central point more clear.)