How is the Bragg condition satisfied for AOMs in a double pass configuration?

  • Thread starter Thread starter Niles
  • Start date Start date
  • Tags Tags
    Optical
AI Thread Summary
In a double pass configuration of acousto-optic modulators (AOMs), the Bragg condition can be satisfied for both the original frequency ω and the shifted frequency ω+Ω due to the small difference between the two frequencies, where Ω is much less than ω. The incoming beam is diffracted at an angle θB during the first pass, and the same angle is used for the second pass with the modified frequency. This consistency in angle is crucial for maintaining the Bragg condition across both passes. The discussion clarifies that the similarity in angles is a key factor in achieving effective modulation. Understanding this principle is essential for optimizing AOM performance in such configurations.
Niles
Messages
1,834
Reaction score
0
Hi

I have a question on AOMs used in a double pass configuration. I understand the motivation for such a setup, but what I don't quite understand is the following: During the first pass, the frequency of the incoming beam is changed from ω to ω+Ω at an angle θB. Then we send the diffracted beam with frequency ω+Ω through the AOM once again at the same angle θB. This last part I don't quite undertand: How can the Bragg condition be satisfied for the angle θB at both ω and ω+Ω?


Niles.
 
Science news on Phys.org
I think the idea is that in general Ω << ω, so the correct angle is essentially the same for the second pass as for the first.
 
Ah, I see. I thought it was most likely something like that, but I was worried that I had misunderstood something. Thanks for taking the time to reply.Niles.
 
Back
Top