- #1
magma_saber
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Homework Statement
Calculate Ea from given info:
ln k = 0 t(sec-1) = 0.0033
ln k = -0.2 t(sec-1) = 0.00335
ln k = -0.4 t(sec-1) = 0.0034
Homework Equations
ln k = -(Ea/RT) + ln A
The Attempt at a Solution
I could find Ea if i had the temperature but I'm given the time. I think you can cancel out the ln A with the temperature can't you? But if you do that, Ea would be in J/K*mol, but Ea should be kJ/mol. This is all from a graph btw and the y intercept = -4515.7x + 14.749 and R2 = 0.9964. Am i suppose to treat this as y=mx + b?