Is there an explanation for the unexpected increase in activity of Nuclide A?

  • Thread starter Thread starter songoku
  • Start date Start date
  • Tags Tags
    Activity
Click For Summary
SUMMARY

The discussion revolves around the unexpected increase in activity of Nuclide A, which is initially calculated to have an activity of 2.84 Bq based on a decay constant of 2.2 x 10-9 s-1 and an initial quantity of 1.29 x 109 nuclei. However, the activity later rises to 10,000 Bq, which contradicts the expected decay behavior. Key insights suggest potential errors in the half-lives of Nuclide A and B or the initial quantity of nuclei, with recommendations to explore "Transient Equilibrium" where the half-life of the parent nuclide exceeds that of the daughter nuclide.

PREREQUISITES
  • Understanding of radioactive decay and decay constants
  • Familiarity with half-life calculations
  • Knowledge of activity calculations using the formula A = λN
  • Concept of Transient Equilibrium in nuclear physics
NEXT STEPS
  • Research "Transient Equilibrium" in nuclear decay series
  • Study the decay series of radionuclides such as 232Th, 235U, and 238U
  • Learn about Secular Equilibrium and its implications in radioactive decay
  • Examine the mathematical derivation of decay constants and activities in nuclear physics
USEFUL FOR

Students and professionals in nuclear physics, radiochemistry, and anyone involved in the study of radioactive decay and its applications.

songoku
Messages
2,509
Reaction score
393
Homework Statement
Nuclide A decays to nuclide B. Initially, there are ##1.29 \times10^9## nuclei of A and after some time the activity of A is 10 000 Bq. If the half life of A and B is 10 years and 10 hours respectively, find activity of B
Relevant Equations
##A=\lambda N##

##t_{\frac 1 2}=\frac{ln~2}{\lambda}##
I found something I think does not make sense.

Decay constant of A:
$$\lambda_{A}=\frac{ln~2}{t_{\frac 1 2}}$$
$$=\frac{ln~2}{10\times 365 \times 24 \times 3600}$$
$$=2.2\times 10^{-9} / s$$

Initial activity of A = ##\lambda_{A} N_{\text{initial}}## = 2.2 x 10-9 x 1.29 x 109 = 2.84 Bq

Then after some time the activity becomes 10 000 Bq. How can the activity increase instead of decrease?

Is there something wrong with the question or something wrong with me?

Thanks
 
Physics news on Phys.org
songoku said:
Is there something wrong with the question or something wrong with me?
There's nothing wrong with you! The question appears to have one or more mistakes.

Some possibilities are:
- the half-lives of A and B are the wrong way round;
- ##1.29 \times10^9## is a very small number for a number of nuclei in this context; maybe it should be ##1.29 \times10^{19}## for example.
 
  • Like
Likes   Reactions: songoku
You could at least obtain the general form of the solution.
 
  • Like
Likes   Reactions: songoku
Thank you very much Steve4Physics and haruspex
 
songoku said:
Homework Statement:: Nuclide A decays to nuclide B. Initially, there are ##1.29 \times10^9## nuclei of A and after some time the activity of A is 10 000 Bq. If the half life of A and B is 10 years and 10 hours respectively, find activity of B
Relevant Equations:: ##A=\lambda N##

##t_{\frac 1 2}=\frac{ln~2}{\lambda}##

Then after some time the activity becomes 10 000 Bq. How can the activity increase instead of decrease?
One should research "Transient Equilibrium", where t1/2(parent) > t1/2(daughter), or λ(parent) < λ(daughter). This is observed for the natural decay series of radionuclides 232Th, 235U, 238U and others.

https://en.wikipedia.org/wiki/Transient_equilibrium
Also see related Secular equilibrium.
 
  • Like
Likes   Reactions: songoku
Astronuc said:
One should research "Transient Equilibrium", where t1/2(parent) > t1/2(daughter), or λ(parent) < λ(daughter). This is observed for the natural decay series of radionuclides 232Th, 235U, 238U and others.

https://en.wikipedia.org/wiki/Transient_equilibrium
Also see related Secular equilibrium.
At this stage it is not clear from @songoku's posts whether he has any difficulty in solving a correctly posed version of the question. The thread centres on the impossible combination of given facts.
 
  • Like
Likes   Reactions: songoku and Orodruin

Similar threads

Replies
13
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
7
Views
6K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K