Actuator on an accelerating body

AI Thread Summary
The discussion centers on calculating the power requirement for a linear actuator attached to a large accelerating body. The actuator must hold a box in place as the body accelerates, raising questions about power consumption during this process. It is clarified that if the actuator is designed to maintain position without power, it would not consume energy when stationary. However, the actuator does require power to counteract the inertia of the box during acceleration, leading to confusion about how to accurately calculate this power requirement. Ultimately, the proper approach involves consulting the actuator's technical specifications to determine its power needs under load.
arjunzv8
Messages
2
Reaction score
0
Hello all, new member here. Signed up cause I am stumped by a physics problem.

I am trying to size a linear actuator. Basically I have a large body that is accelerating at acceleration in x direction. I have a linear actuator aligned in the x direction that is rigidly attached to the large body on one end and the other end is touching a box. The actuator has to hold the box (mass m) in place relative to the large body.

If the large body is accelerating at "a" till it reaches velocity "v", what is the power requirement of the actuator. For simplicity, I am ignoring air drag, actuator efficiency etc.

Attached image shows the setup.

Is this a non-inertial frame?
Is the actuator consuming power even if there is no motion (relative between actuator and box) because of the inertia of the box?
Is it correct if I calculate power requirement as shown below?
F=ma
Distance d=0.5*a*t^2
Time t=v/a
Power P=F*d/t

Since I am ignoring air drag, power is consumed only during acceleration correct?
 

Attachments

  • actuator.jpg
    actuator.jpg
    23.6 KB · Views: 498
Physics news on Phys.org
arjunzv8 said:
I am ignoring air drag, actuator efficiency etc...Is the actuator consuming power even if there is no motion (relative between actuator and box) because of the inertia of the box?
If you ignore actuator efficiency, then no power is required. You could replace the actuator with a rigid attachment which also consumes no power.
 
  • Like
Likes arjunzv8
I am still confused by this. Unlike a rigid attachment, an actuator would still consume power to remain in position as long as there is a load (here that is F=ma during the acceleration). So how would I then calculate this power requirement.
 
arjunzv8 said:
So how would I then calculate this power requirement.
From the technical specifications of the actuator. Ideally you would use one, that can be locked in a static position without power consumption.
 
  • Like
Likes arjunzv8
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...
Back
Top