ADC converter question about the LSB

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SUMMARY

The discussion centers on understanding the least significant bit (LSB) in the context of an ADC (Analog-to-Digital Converter) and its relationship to the change in the analog signal. The LSB corresponds to a change in the analog signal of V/(2^N-1), where V is the reference voltage and N is the number of bits. The participant struggles with the concept of how the LSB relates to the amplitude change in the analog signal, particularly in a 5-volt ADC system. The key takeaway is that the smallest voltage increment that can be represented by the ADC is determined by this formula.

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Homework Statement


Show that the least significant bit (LSB) corresponds to a change in the analog signal of V/(2^N-1).


Homework Equations


D=b_0 * 2^0 +b_1 * 2^1 + ... + b_(N-1) * 2^(N-1), where b_0 is the LSB, and b_(N-1) is the MSB.



The Attempt at a Solution


I have absolutely have no idea what they are asking or how to solve it. I tried using the fact that 0 means logic 0 (off) and V means logic 1 (on). I think that the change in analog signal that they are talking about means that from when the bit number changes from the LSB to the next bit number, the change in amplitude of the analog signal. I tried that fact that 2^0 equals 1, and plugged that into the given expression, but that still did not make any sense. Does "correspond" mean that the LSB is proportional, or equal to the change in analog signal?
How can I solve this problem?
 
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You have a 5 volt chip. The lowest value it can read is 0 volts and that's a 0 after conversion. The largest value is for 5 volts and will be read as all bits = 11111...1.

The question is, how many volts will get converted into 000...001?
 
Thank you very much! This helped a lot.
 

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