Adiabatic compression of an ideal gas

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SUMMARY

The discussion focuses on the adiabatic compression of an ideal gas, specifically calculating the final temperature after compressing from an initial volume of 70.0 liters to a final volume of 43.0 liters at an initial temperature of 17.7°C, with a specific heat at constant volume (CV) of 2.50R. The relationship used is T1V^γ = T2V^γ, where γ is the ratio of specific heats (C_p/C_v). The discussion emphasizes that while the number of moles (n) cannot be determined without pressure, it is not necessary for solving the problem, as the adiabatic condition can be applied directly to find the final temperature.

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  • Familiarity with specific heat capacities (C_p and C_v)
  • Basic algebra for manipulating equations
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Rasine
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An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R.


so T1V1^g=T2V2^g


to find g=cp/cv=(cv+nR)/cv and cv=2.50R

g=(2.50R+nR)/2.50R factor out an R g=(2.50+n)/2.50 factor out 2.50

g=n/2.50

but how do i find n...if what i did above is even right
 
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Rasine said:
An ideal gas at a temperature of 17.7°C is compressed adiabatically from an initial volume 70.0 l to a final volume 43.0 l. Find its final temperature (in °C) if CV = 2.50R. so T1V1^g=T2V2^g
It helps to start with the correct relationship. The adiabatic condition is:

PV^\gamma = K

Substitute P = nRT/V to give:

TV^{\gamma-1} = K/nR = constant

You can't determine what n is since you don't have the pressure. But you don't need it to solve the question.

AM
 
Last edited:
so how do i get what i denoted as g
 
do i solve for what ever nR is
 
i am so confused! please give me another hint
 
Rasine said:
i am so confused! please give me another hint
What is TV^{\gamma-1} initially?

Does it change?

So what is it at the end?

You are given the volume at the end. So what is T at the end?

Note: \gamma = C_p/C_v \text{ and } C_p = C_v + R

\gamma is simply a ratio of specific heats so it is dimensionless.

AM
 

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