Adiabatic Process for an Ideal Gas

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SUMMARY

The discussion focuses on the adiabatic process of an ideal gas, specifically in the context of a gasoline engine's compression stroke. The pressure increases from 1.00 atm to 20.3 atm, with a specific heat ratio (gamma) of 1.40. Key calculations involve determining the volume change factor (Vfinal = (ans)*Vinitial), the temperature change factor (Tfinal = (ans)*Tinitial), and the thermodynamic properties Q, W, and Eint, where Q = 0 for adiabatic processes, leading to the relationship dE = dW.

PREREQUISITES
  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with the ideal gas law (PV = nRT)
  • Knowledge of specific heat ratios (gamma) and their implications
  • Ability to perform integration in thermodynamic calculations
NEXT STEPS
  • Study the derivation of the adiabatic process equations for ideal gases
  • Learn about the implications of the first law of thermodynamics in adiabatic processes
  • Explore the concept of work done during compression in thermodynamic systems
  • Investigate the relationship between pressure, volume, and temperature changes in adiabatic processes
USEFUL FOR

Students of thermodynamics, mechanical engineers, and anyone involved in the design or analysis of internal combustion engines.

cmilho10
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During the compression stroke of a certain gasoline engine, the pressure increases from 1.00 atm to 20.3 atm. Assume that the process is adiabatic and the gas is ideal with (gamma)= 1.40.

(a) By what factor does the volume change?
Vfinal = (ans)*Vinitial
(b) By what factor does the temperature change (when expressed using an absolute scale)?
Tfinal =(ans) * Tinitial
(c) If the compression starts with 0.0160 mole of gas at 27.5°C, find the values of Q, W, and Eint that characterize the process.

I know the relationship is described by PV^(gamma)=constant but am clueless on how to apply this to get the answers.
 
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pv ^ gamma = constant means you can write

Pi Vi ^gamma = Pf Vf^gamma. You need to simply rearrange this equation to get Vi/Vf.

for part b:

From PV = nRT, you can write Pi Vi/Ti = Pf Vf /Tf

Since you already know Pi/Pf and Vi/Vf, rearrange the above to get Ti/Tf.

For part c.

If i remember correct for adiabetic process, Q=0. So change in internal energy, dE = dW

and work done on the system W = -intgration (dW) = -intgration (PdV)
where P= nRT/V


Limit of integration is Vi to Vf. You will have to use the given info about mole number and temperature to find vi and vf.
 

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