Advanced Math Problem of the Week 9/30/2017

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  • Thread starter Thread starter PF PotW Robot
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SUMMARY

The advanced math problem presented involves proving the integral $$\int_0^\infty \sin(x^\alpha)\, dx = \sin\left(\frac{\pi}{2\alpha}\right)\,\Gamma\!\left(1 + \frac{1}{\alpha}\right)$$ for values of α greater than 1. The discussion emphasizes the importance of contour integration as a method for solving this problem. Participants are encouraged to explore alternative solution methods, with potential prizes for innovative approaches. The issue of indeterminacy at α=1 is acknowledged, reinforcing the necessity of the condition α>1.

PREREQUISITES
  • Understanding of contour integration techniques
  • Familiarity with the Gamma function and its properties
  • Knowledge of sine integrals and their convergence
  • Basic principles of complex analysis
NEXT STEPS
  • Research advanced contour integration methods
  • Study the properties of the Gamma function in detail
  • Explore alternative proofs for sine integrals
  • Investigate the implications of indeterminate forms in calculus
USEFUL FOR

Mathematicians, advanced calculus students, and anyone interested in complex analysis and integral calculus will benefit from this discussion.

PF PotW Robot
Here is this week's advanced math problem of the week. We have several members who will check solutions, but we also welcome the community in general to step in. We also encourage finding different methods to the solution. If one has been found, see if there is another way. Occasionally there will be prizes for extraordinary or clever methods. Spoiler tags are optional.

Using contour integration, prove

$$\int_0^\infty \sin(x^\alpha)\, dx = \sin\left(\frac{\pi}{2\alpha}\right)\,\Gamma\!\left(1 + \frac{1}{\alpha}\right),\quad \alpha > 1.$$

(PotW thanks to our friends at http://www.mathhelpboards.com/)
 
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Something seems quite odd here. For α=1 the RHS =1, but the LHS is indeterminate = -cos(∞)-1.

My mistake. That is why α>1.
 

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