Air Drag Formula: Solving Maik's Rocket Project Challenge

AI Thread Summary
Maik is developing a formula to calculate the height of solid fuel rockets, factoring in air drag, but faces a challenge due to the interdependence of rocket speed and air drag. The air drag equation, Fd(t) = -0.5 * p * A * Cd * v^2, complicates the calculation since both speed and acceleration are influenced by drag. This leads to a differential equation where the drag force depends on its own value, making it difficult to solve. A suggestion is made that the relationship between acceleration and velocity is not straightforward, as acceleration can vary over time. Overall, Maik seeks a method to accurately account for air drag in his rocket height calculations.
v6maik
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Hello,

I'm working on a project about solid fuel rockets and since these are moving through the atmosphere, they experience Air-drag. I'm trying to set up a formula to exactly calculate the height a rocket will achieve. So without the use of any model. The problem I ran into is that I can't get the formula for acceleration to include air-drag, since I ran into the following loop:

-the speed of the rocket (and thereby the acceleration) depends on the air-drag.
-the air-drag depends on the speed of the rocket (and thereby the acceleration)

I found this equation for air-drag but it's of no use in its current form.

Fd(t)= -0,5 * p * A * Cd * v^2

as you can see, drag depends on the speed relative to the air-mass, which is pretty obvious.

But since v=a * t, this formula is the same as:

Fd(t)= -0,5 * p * A * Cd * (a*t)^2

and since a= F/m this formula is the same as:

Fd(t)= -0,5 * p * A * Cd (((F / m ) *t)^2

note that F is the net Force on the rocket. The net Force at a given time is equivalent to the propulsion force minus gravity minus drag:

Fnet(t)= Fp(t) - Fg(t) - Fd(t)

So the drag formula now is:

Fd(t)= -0,5 * p * A * Cd (((Fm(t) - Fg(t) - Fd(t)) / m ) *t)^2

Notice that this formula Fd(t) involves it's own answer, so it is a differential equasion, right?

Now, I can simplify this formula to this, leaving 3 constants: a, b and c:

Fd(t)= a * ( (b-Fd(t) )/c * t)^2

Any suggestions about solving this problem? Or might there be a different equation to calculate air-drag at a given time during acceleration?

Thanks ahead!

Kind regards,
Maik
 
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There isn't anyone formula for drag that works for high speeds, especially transonic and supersonic speed. The mathematical model for bullets and cannon shells is complex, relies on the usage of tables from actual measured data, and it wasn't until around 1990 (Desert Storm), that tanks (USA tanks) could reliably shoot other tanks with a single shot with advanced fire control systems.
 
v6maik said:
Hello,

I'm working on a project about solid fuel rockets and since these are moving through the atmosphere, they experience Air-drag. I'm trying to set up a formula to exactly calculate the height a rocket will achieve. So without the use of any model. The problem I ran into is that I can't get the formula for acceleration to include air-drag, since I ran into the following loop:

-the speed of the rocket (and thereby the acceleration) depends on the air-drag.
-the air-drag depends on the speed of the rocket (and thereby the acceleration)

I found this equation for air-drag but it's of no use in its current form.

Fd(t)= -0,5 * p * A * Cd * v^2

as you can see, drag depends on the speed relative to the air-mass, which is pretty obvious.

But since v=a * t,

no. that is only true if the acceleration is constant (and if the velocity is zero at t=0). In general
<br /> a=\frac{dv}{dt}<br />
and so
<br /> v(t)=v(0)+\int_0^t a(t) dt<br />
 
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