Air pressure variation with height

AI Thread Summary
The pressure exerted by a column of air is significantly less than that of water due to the difference in density. While a 10-meter depth of water corresponds to approximately one atmosphere of pressure, the same height in air results in a much smaller pressure difference. Specifically, a 10-meter column of air would only create about 0.001 bar of pressure difference, not 1 bar. This is because the atmosphere extends roughly 10,000 meters high, making the pressure variation with height much less pronounced in air. Understanding these principles is crucial for accurately applying them in pneumatic systems.
jranjit
Messages
1
Reaction score
0
Hi,

I understand the thumb rule that " the pressure exerted by ten metres depth of water is approximately equal to one atmosphere". Is it applicable for pneumatic systems too ?? that with 10 m head difference in air pressure lines there would be 1 bar difference in pressure between the ends

Please advise
 
Last edited:
Physics news on Phys.org
10m of water weighs the same as all the air above your head - so 10m of air is unlikely to weigh the same.
If the atmosphere is roughly 10,000m high then 10m head is about 10/10,000 of a bar different - otherwise you would need to decompress when standing up.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top