Air temperature in soda bottle pumped to 8 atm

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    Air Temperature
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Discussion Overview

The discussion revolves around the relationship between air temperature and pressure in a soda bottle when pumped to 8 atm. Participants explore theoretical expectations, practical observations, and the underlying physics principles, including gas laws and thermodynamics.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the expected temperature could be around 2400 K when the pressure is increased to 8 atm, questioning why no melting occurs in the bottle.
  • Others challenge the initial assumptions about temperature and pressure relationships, asking for clarification on initial and process conditions.
  • Concerns are raised about the safety of the experiment, with one participant warning that an explosion could occur if the bottle behaved as expected.
  • Some participants argue that increasing pressure does not necessarily lead to a linear increase in temperature, suggesting that the mass of air added affects the temperature differently.
  • One participant references the combined gas law and discusses how changes in pressure and volume relate to temperature, expressing confusion about the calculations involved.
  • Another participant explains that the volume refers to the space occupied by the air, and that compressing air without heating it will not achieve the expected temperature increase.
  • Some participants note that the bottle feels warmer after pumping and that releasing pressure causes cooling, suggesting possible liquefaction of gases.
  • One participant clarifies that the bike pump increases the number of air molecules in the bottle, which affects temperature but does not reach the extreme values initially expected.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the relationship between pressure, temperature, and volume. There is no consensus on the expected outcomes or the underlying principles, with ongoing debate about the calculations and safety implications.

Contextual Notes

Limitations include unclear initial conditions, assumptions about the behavior of gases under pressure, and the specific definitions of volume in the context of the discussion.

SMD1990
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In theory, it should be about 2400 K, no? Yet, the bottle does not show any melting. I cannot even get a little piece of solder inside to melt. Is the heat loss during the thirty to sixty seconds of pumping that extreme? Or, is my understanding of the relationship between temperature and pressure incorrect?
 
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2400K?
What are your initial conditions?
what are the conditions during the process?
what relationship between temperature and pressure do you have in mind?
 
First, what you are doing is very, very dangerous. You should stop immediately.

What the heck were you thinking? If things worked as you expected, you'd have an explosion with blobs of red-hot molten glass everywhere?

Second, why do you think increasing the pressure will increase the temperature?
 
SMD1990 said:
In theory, it should be about 2400 K, no? Yet, the bottle does not show any melting. I cannot even get a little piece of solder inside to melt. Is the heat loss during the thirty to sixty seconds of pumping that extreme?

Absolutely no way.

SMD1990 said:
Or, is my understanding of the relationship between temperature and pressure incorrect?

You are adding air right? If you have more mass in a volume to generate a certain amount of pressure, the less the temperature has to be to generate a certain amount of pressure. So your pressure goes up without a linear increase of temperature.
 
I have read that soda bottles (plastic) can withstand 150 psi or more. I am not certain, but I think about 14 psi is around atmospheric pressure (101.325 kPa).

I thought:
increased pressure = increased temperature
decreased volume = increased pressure (and therefore, increased temperature)
decreased pressure = decreased temperature
increased volume = decreased pressure (and therefore, decreased temperature)​

http://easycalculation.com/chemistry/combined-gas-law.php" online calculator affirms what I thought.

And, since I was octupling the pressure of room temperature air, I was expecting 298.15 * 8 = 2385.2 K. Or perhaps, the average of the temperature increases of each downward stroke of the bike pump.
 
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If the bottle behaved as you thought it would, you'd have an explosion of molten glass (or burning plastic). It was an exceptionally stupid thing that you did, and the fact that you are defending it concerns me deeply.

The reason the calculator gives you the wrong answer is because you are plugging the wrong numbers into it. What is your final volume? What is your initial volume?
 
Considering the bottle remains basically unchanged, the initial and final volumes are the same, no? Or, does "volume" refer to the amount of air, irrespective of its confinement within a fixed "volume"?

Ever heard of a water rocket? They typically use pressures of 75 to 150 psi, and bottles similar to what I have been using. (I have also been trying with a clogged syringe, but that is besides the point.)

I am not after extremely high temperatures. However, since doubling or tripling the pressure did not do the same to the temperature, I opted for higher pressures.

The bottle feels warmer after pumping. And, if I quickly release the pressure, it gets quite cool. Some drops of liquid can even be seen. Cool enough to liquify one of more of the gases in the air?
 
SMD1990 said:
Considering the bottle remains basically unchanged, the initial and final volumes are the same, no? Or, does "volume" refer to the amount of air, irrespective of its confinement within a fixed "volume"?

The volume refers to space occupied by a fixed amount of substance. When you pressurized the air, you added more air, so the original amount of air occupies less space. If your volume and pressure are inversely-related, then the temperature does not change. However, if your temperature slightly increases, that means that pressure increased by a factor greater than the factor by which the volume decreased. So if you increase pressure by a factor of 6 and decrease volume by a factor of 2, then your temperature would triple. You won't be able to achieve that without heating the air though. You can't just compress it with air at the same temperature. It won't work like that.
 
Oh, okay. Now I understand. Thank you for explaining!
 
  • #10
PV = nRT.

V is essentially constant.

The bike pump may increase pressure by 8 times. This means that n * T is 8 times greater. You can see T is warmer than when you started, but not by that much... mostly what the pump does is put more air molecules into the bottle.

Your analysis was treating the pump like a heater. You would indeed need to heat the bottle's air to around 2400K to get that pressure, assuming you put no more air molecules inside, and were just heating the ones that were in there to start with.
 

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