- #1

- 161

- 0

pretty simple i no but i still keep making mistakes somewhere.

i can get it down to: 4800/6400=(cos ̂)^2 + (sin ̂)^2

but then i get a little stuck.

by the way ̂=thetre=unkown angle.

good luck

i need it.

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- Thread starter brandy
- Start date

- #1

- 161

- 0

pretty simple i no but i still keep making mistakes somewhere.

i can get it down to: 4800/6400=(cos ̂)^2 + (sin ̂)^2

but then i get a little stuck.

by the way ̂=thetre=unkown angle.

good luck

i need it.

- #2

- 1,074

- 1

- #3

- 161

- 0

^{2}(x) + cos^{2}(x) = 1 for all values of x and 4800/6400 is not equal to 1, thus the equation is simply false.

yea i figured that out just before. oops. mybad. but how could you rearange a similar equation so that it equalled thetre.

im not very intelligent if u havent already noticed.

no wait scratch that. how could u rearrange the equation x=(cos thetre)^2 + (sin thetre)^2

even though my original numbers were incorrect.

Last edited:

- #4

- 1,074

- 1

yea i figured that out just before. oops. mybad. but how could you rearange a similar equation so that it equalled thetre.

im not very intelligent if u havent already noticed.

no wait scratch that. how could u rearrange the equation x=(cos thetre)^2 + (sin thetre)^2

even though my original numbers were incorrect.

in that situation x must be 1, it cannot have any other value if that is to be a true statement.

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