Rohan said:
Quite likely:
"A proof that algebraic topology can never have a non self-contradictory set of Abelian groups".
is rubbish; but shouldn't we start from the term , " set of Abelian groups". ?
(I have recently got up to here in my attempt to understand modern mathematics
so as a beginner please correct me if I am not understanding !)
- A group is just a set, for which an operation eg * is defined
Yes, where this binary operation obeys certain rules.
(I like to think of the multiplication of square matrices !)
Those do not obey these rules in general. Better think of the multiplication of non zero numbers, or invertible square matrices.
-ordinary groups have the properties of (a)closure (b) associativity (c)identity (d)inversion and
Yes, that is one way to define it.
-an "Abelian group" is just a group with the additional property of (e) commutation ( eg A x B = B x A for square matrices)
Again, not in general. Matrix multiplication is "far more often" not commutative, as it is commutative.
Thus " a set of Abelian groups", could mean a set of these, now sets can famously contain all kinds of things.
Almost all.
I seem to recall one as part of a famous paradox which " was the set of all sets , which do not contain themselves";
which was described as a "contradictory set" ?
This certain set is excluded for a set if properly defined. Thus, and even for pure linguistic reasons, the term "contradictory set" doesn't make sense. It simply does not say in what the contradiction lies. E.g. we can talk about self-contradiction of a system, i.e. a set of rules which when applied create a contradiction. This demonstrates the next reason why "contradictory set" is nonsense: A contradiction means a conclusion leads to ##true = false##, and a set per se cannot do this. Only its elements, so they are conclusion laws can do this. Abelian groups are no rules, and I've never heard of a binary operation on rules, let alone a commutative. One might be able to construct such a thing, but even then, the specification "Abelian groups" is far too general. And on top: neither of these things has anything to do with algebraic topology.
Thus couldn't the statement "that algebraic topology can never have a non self-contradictory set of Abelian groups";
be interpreted as stating ' all sets of Abellian groups in algebaic topology are contradictory ?'
No, as contradictory to what is still missing. An abelian group cannot be "contradictory" regardless how many you sample in a set.
Of course what this means and whether it is true are well beyond my ability !
The only sense why this quote has found its way into the show is, that all words in it can be looked up on Wikipedia and most people won't understand a single one of them. Fact-check-proof isn't intended in a tv-show.